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Re: A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 [#permalink]
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pushpitkc wrote:
A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 girls. Sam, who is one of the boys,
is selected only if his sister, Eloise, who is one of the girls is also selected. In all, how many different teams
are possible?

A. 315
B. 630
C. 1015
D. 1540
E. 2450

Source: Experts Global


Favourable cases = Total ways of selecting team - teams with the brother without sister = 7C4*8C5 - 6C3*7C5 = 35*56 - 20*21 = 1540
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Re: A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 [#permalink]
saraheja wrote:
Two cases :

1) When boy is selected so for sure girl would have been selected , so no. of ways would be 6C3 * 7C4 = 700

2) When that boy is not selected - 6C4 * 8C5 = 840

total 1540


I did the same calculation. How did you get 840 from 6C4 * 8C5 ? I constantly get (15*42) = 630.
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A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 [#permalink]
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GMATinsight wrote:
pushpitkc wrote:
A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 girls. Sam, who is one of the boys,
is selected only if his sister, Eloise, who is one of the girls is also selected. In all, how many different teams
are possible?

A. 315
B. 630
C. 1015
D. 1540
E. 2450

Source: Experts Global


Favourable cases = Total ways of selecting team - teams with the brother without sister = 7C4*8C5 - 6C3*7C5 = 35*56 - 20*21 = 1540


Does that mean that there is a number of outcomes included in 1540, in which the sister can go without brother? Because I see that you deducted only the case when brother goes without sister. Thanks
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Re: A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 [#permalink]
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Hero8888 wrote:
saraheja wrote:
Two cases :

1) When boy is selected so for sure girl would have been selected , so no. of ways would be 6C3 * 7C4 = 700

2) When that boy is not selected - 6C4 * 8C5 = 840

total 1540


I did the same calculation. How did you get 840 from 6C4 * 8C5 ? I constantly get (15*42) = 630.


8C5 = 8!/3! 5! = 56,
6C4 * 8C5 = 15 * 56 = 840
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Re: A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 [#permalink]
RidhimaGmat wrote:
Hero8888 wrote:
saraheja wrote:
Two cases :

1) When boy is selected so for sure girl would have been selected , so no. of ways would be 6C3 * 7C4 = 700

2) When that boy is not selected - 6C4 * 8C5 = 840

total 1540


I did the same calculation. How did you get 840 from 6C4 * 8C5 ? I constantly get (15*42) = 630.


8C5 = 8!/3! 5! = 56,
6C4 * 8C5 = 15 * 56 = 840


Omg, my arithmetic sucks, thanks.
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Re: A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 [#permalink]
pushpitkc wrote:
A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 girls. Sam, who is one of the boys, is selected only if his sister, Eloise, who is one of the girls is also selected. In all, how many different teams are possible?

A. 315
B. 630
C. 1015
D. 1540
E. 2450

Source: Experts Global
Both selected - 6c3 + 7c4

Sam not selected - 6c4 + 8c5

We add the above two to get the answer.

Remember spending a lot of time on this one while attempting Experts Global mock and getting it incorrect :(

Sent from my SM-T285 using GMAT Club Forum mobile app
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Re: A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 [#permalink]
Hero8888 wrote:
GMATinsight wrote:
pushpitkc wrote:
A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 girls. Sam, who is one of the boys,
is selected only if his sister, Eloise, who is one of the girls is also selected. In all, how many different teams
are possible?

A. 315
B. 630
C. 1015
D. 1540
E. 2450

Source: Experts Global


Favourable cases = Total ways of selecting team - teams with the brother without sister = 7C4*8C5 - 6C3*7C5 = 35*56 - 20*21 = 1540


Does that mean that there is a number of outcomes included in 1540, in which the sister can go without brother? Because I see that you deducted only the case when brother goes without sister. Thanks
Yes, my friend. That is the catch in the question.

Reading carefully. The brother comes only if sister does but the sister can come alone.

It's so important to understand the nuanced meaning in such questions.

Good stuff.

Sent from my SM-T285 using GMAT Club Forum mobile app
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Re: A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 [#permalink]
pushpitkc wrote:
A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 girls. Sam, who is one of the boys, is selected only if his sister, Eloise, who is one of the girls is also selected. In all, how many different teams are possible?

A. 315
B. 630
C. 1015
D. 1540
E. 2450

Source: Experts Global

1. Total boys and girls are \(7\) and \(8\) respectively. And \(4\) boys and \(5\) girls are to be selected for the team

2. There will be \(3\) cases. Let's assume variables for Eloise getting selected as \(E\) and not getting selecting as \(NE\). Similarly, \(S\) and \(NS\) for Sam

CASE - I: \(E\) & \(S\) \(= (1 * 7C4) * (1 * 6C3) = 35 * 20 = 700\)

CASE - II: \(E\) & \(NS\) \(= (1 * 7C4) * (6C4) = 35 * 15 = 525\)

CASE - III: \(NE\) & \(NS\) \(= (7C5) * (6C4) = 21 * 15 = 315\)

3. Summing up the three cases \(= 700 + 525 + 315 = 1,540\)

Ans. D
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Re: A team of 4 boys and 5 girls is to be made from a team of 7 boys and 8 [#permalink]
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