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Re: In the given figure ABCD is a rectangle and EF || AD. AEG and FEB are [#permalink]
chillbrorelax, you are saying that AE * GE = 2 * EF * EB. But the question says that area of AEG is half the one for FEB. Should it not be 2 * AE * GE = EF * EB?
Thanks !
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Re: In the given figure ABCD is a rectangle and EF || AD. AEG and FEB are [#permalink]
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Answer should be C. Both together are sufficient.

(1) EBCF is a square of side length 5 centimeters.
not sufficient as we don't know if the other part of he rectangle is a square with same length or no ; we dont even know if its a square or another rectangle in the first place.

(2) A line passing through point G and parallel to AB divides the rectangle ABCD into 2 equal halves.
If the rectangle is divided in two half that means the halves have an equal area but we do not know the dimensions of the two halves.
hence insufficient.

combining both we get the dimensions as well as the information pertaining to the kind of polygon the two halves are (whether rectangle or square)

therefore the two are sufficient to answer the question.

Area is 2*5*5=50 sq.units
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Re: In the given figure ABCD is a rectangle and EF || AD. AEG and FEB are [#permalink]
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In the given figure ABCD is a rectangle and EF || AD. AEG and FEB are two triangles inscribed in the rectangle ABCD such that the area of triangle AEG is half of the area of triangle FEB. What is the area of rectangle ABCD?

(1) EBCF is a square of side length 5 centimeters.
No information is given for AEFD.

Not sufficient

(2) A line passing through point G and parallel to AB divides the rectangle ABCD into 2 equal halves
So, G is the mid point of EF.
Also, area AEG = (1/4) area AEFD
But, no length is given for sides, area can not be determined.

Not sufficient

(1) + (2),
EBCF is a square of side length 5 centimeters
which gives, area of triangle FEB = 25/2
So, area of triangle AEG = 25/4
Therefore, area of AEFD. = 25
area of ABCD can be determined.

Hence sufficient

Choice C
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Re: In the given figure ABCD is a rectangle and EF || AD. AEG and FEB are [#permalink]
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Re: In the given figure ABCD is a rectangle and EF || AD. AEG and FEB are [#permalink]
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