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If snow accumulation increased at a constant rate of 30 millimeters pe

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Nanobotstv
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If snow accumulation increased at a constant rate of 30 millimeters pe [#permalink] New post   09 May 2018, 03:34
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If snow accumulation increased at a constant rate of 30 millimeters per hour during a certain snowstorm, how many seconds did it take for snow accumulation to increase by 1 millimeter?

A. 1/120
B. 1/60
C. 1/20
D. 20
E. 120
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E
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BrentGMATPrepNow
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Re: If snow accumulation increased at a constant rate of 30 millimeters pe [#permalink] New post   09 May 2018, 07:08
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alanforde800Maximus wrote:
If snow accumulation increased at a constant rate of 30 millimeters per hour during a certain snowstorm, how many seconds did it take for snow accumulation to increase by 1 millimeter?

a) 1/120
b) 1/60
c) 1/20
d) 20
e) 120


Let's keep listing EQUIVALENT RATES until we get to 1 millimeter

30 millimeters per hour = 30 millimeters per 60 minutes
= 30 millimeters per 3600 SECONDS
= 3 millimeters per 360 SECONDS
= 1 millimeter per 120 SECONDS

Answer: E

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Re: If snow accumulation increased at a constant rate of 30 millimeters pe [#permalink] New post   09 May 2018, 08:59
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alanforde800Maximus wrote:
If snow accumulation increased at a constant rate of 30 millimeters per hour during a certain snowstorm, how many seconds did it take for snow accumulation to increase by 1 millimeter?

a) 1/120
b) 1/60
c) 1/20
d) 20
e) 120

I suspect the trap answer is A. It is easy to overlook units.

Shortcut: 1 hour = 3600 seconds
\(\frac{30mm}{1hour}=\frac{30mm}{3600secs}=\frac{1mm}{120secs}\)

Units are not the same. The answer is not A. In 120 seconds, 1mm of snow will accumulate.

Answer E

No shortcut: \((\frac{30mm}{1hour}*\frac{1hour}{60mins}*\frac{1min}{60secs})=\frac{30mm}{(60*60)secs}=\frac{30mm}{3600secs}\)

In the parentheses, hours and minutes cancel. Factor out 30, write the final units: \(\frac{1mm}{120secs}\)

Answer E
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Re: If snow accumulation increased at a constant rate of 30 millimeters pe [#permalink] New post   10 May 2018, 10:40
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alanforde800Maximus wrote:
If snow accumulation increased at a constant rate of 30 millimeters per hour during a certain snowstorm, how many seconds did it take for snow accumulation to increase by 1 millimeter?

a) 1/120
b) 1/60
c) 1/20
d) 20
e) 120


Recalling that 1 hour = 3600 seconds, we can create the equation:

30/3600 = 1/x

1/120 = 1/x

x = 120

Answer: E
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Re: If snow accumulation increased at a constant rate of 30 millimeters pe [#permalink] New post   11 Sep 2018, 09:59
I haven't seen on GMATCLUB the method that I use (that I was taught in my school to convert ratios). I hope it will be helpful, at least it makes my life easier. See attachment below
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Re: If snow accumulation increased at a constant rate of 30 millimeters pe [#permalink] New post   13 Sep 2019, 23:34
Nanobotstv wrote:
If snow accumulation increased at a constant rate of 30 millimeters per hour during a certain snowstorm, how many seconds did it take for snow accumulation to increase by 1 millimeter?

a) 1/120
b) 1/60
c) 1/20
d) 20
e) 120



Given: Snow accumulation increased at a constant rate of 30 millimeters per hour during a certain snowstorm.

Asked: How many seconds did it take for snow accumulation to increase by 1 millimeter?

30 millimeters snow is accumulated in 1 hours = 3600 seconds
1 millimetre snow will be accumulated in = 3600/30 = 120 seconds

IMO E
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Re: If snow accumulation increased at a constant rate of 30 millimeters pe [#permalink] New post   23 Nov 2020, 10:04
Nanobotstv wrote:
If snow accumulation increased at a constant rate of 30 millimeters per hour during a certain snowstorm, how many seconds did it take for snow accumulation to increase by 1 millimeter?

a) 1/120
b) 1/60
c) 1/20
d) 20
e) 120



30 millimeters = 1 hour
\(\frac{1}{2}\) millimeters = 1 minute
\(\frac{1}{120}\) millimeters = 1 second

\(\frac{1}{120} * 120 seconds = 1 millimeter\)

Answer is E.
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Re: If snow accumulation increased at a constant rate of 30 millimeters pe [#permalink] New post   14 May 2023, 09:14
Hello from the GMAT Club BumpBot!

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Re: If snow accumulation increased at a constant rate of 30 millimeters pe [#permalink]
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