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As shown above, a rectangle is divided into smaller rectangles of the [#permalink]
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TestPrepUnlimited wrote:
Bunuel wrote:

As shown above, a rectangle is divided into smaller rectangles of the same size and shape. What is the perimeter of the large rectangle?

(1) The length of the darkened path on the right is 36.
(2) The length of the darkened path on the left is 54.

DS21216

Attachment:
21216.png


A rectangle has two variables to consider, length and width. However, from the graph we can tell 2*Width = 1*Length. Thus the rectangle can be defined by one variable of width, and the length is two times width.

Statement 1:

We can count how many lengths and widths we need to add up but ultimately it will be some multiple of width = 36, thus we can solve for width and then the length. Sufficient.

Statement 2:

Same as above, sufficient.

Ans: D


Bunuel,

How can we infer from the graph that 2*Width = 1*Length ? I considered length = x and width = y. So, the perimeter of the larger rectangle = 6(2x + y).

From (1), we get 3(x + 2y) = 36 and from (2), we get 2(2x + 5y) = 54 => we get values of x and y; thus, both statements together sufficient.

Pl. expln.
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Re: As shown above, a rectangle is divided into smaller rectangles of the [#permalink]
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jack0997 wrote:
TestPrepUnlimited wrote:
Bunuel wrote:

As shown above, a rectangle is divided into smaller rectangles of the same size and shape. What is the perimeter of the large rectangle?

(1) The length of the darkened path on the right is 36.
(2) The length of the darkened path on the left is 54.

DS21216

Attachment:
21216.png


A rectangle has two variables to consider, length and width. However, from the graph we can tell 2*Width = 1*Length. Thus the rectangle can be defined by one variable of width, and the length is two times width.

Statement 1:

We can count how many lengths and widths we need to add up but ultimately it will be some multiple of width = 36, thus we can solve for width and then the length. Sufficient.

Statement 2:

Same as above, sufficient.

Ans: D


Bunuel,

How can we infer from the graph that 2*Width = 1*Length ? I considered length = x and width = y. So, the perimeter of the larger rectangle = 6(2x + y).

From (1), we get 3(x + 2y) = 36 and from (2), we get 2(2x + 5y) = 54 => we get values of x and y; thus, both statements together sufficient.

Pl. expln.


Look at the image. Notice that the length of 4 rectangles equals to the width of 8 rectangles. So, length = 2*width
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Re: As shown above, a rectangle is divided into smaller rectangles of the [#permalink]
length =x and width = y and if we carefully observe x =2y. so if we know x or y then sufficient to find perimeter of r large rectangle.

large rectangle perimeter = 12x +6y = 12x or 24y
1. length of darkened path on the right -3x+6y =>6x =>6x= 36 =>x=6=>12x =>72=> SUFFICIENT
2.length of darkened path on the left-4x+10y =9x= 54=> x=6=> 12x=>72= SUFFICIENT
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Re: As shown above, a rectangle is divided into smaller rectangles of the [#permalink]
Look at the picture
Attachment:
fig.png
fig.png [ 368.1 KiB | Viewed 4261 times ]


from each statement you can get the wide of the tile, and from it the perimeter od the figure.

D
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Re: As shown above, a rectangle is divided into smaller rectangles of the [#permalink]
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Re: As shown above, a rectangle is divided into smaller rectangles of the [#permalink]
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