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In the figure above, the areas of square regions X and Y are 1 and 4,

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Bunuel
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In the figure above, the areas of square regions X and Y are 1 and 4, [#permalink] New post   20 Jan 2021, 01:15
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In the figure above, the areas of square regions X and Y are 1 and 4, respectively. What is the area of the triangular region?

A. 2

B. 1

C. 3/4

D. 1/2

E. 1/4



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CrackverbalGMAT
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In the figure above, the areas of square regions X and Y are 1 and 4, [#permalink] New post   Updated on: 20 Jan 2021, 04:14
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The triangle is right angled. The base and height of the triangle = 1 and 2 respectively, since the 2 squares lie on the sides of the triangle.

Area = 1/2 * base * height = 1/2 * 1 * 2 = 1


Option B

Arun Kumar

Originally posted by CrackverbalGMAT on 20 Jan 2021, 04:04.
Last edited by CrackverbalGMAT on 20 Jan 2021, 04:14, edited 1 time in total.
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Re: In the figure above, the areas of square regions X and Y are 1 and 4, [#permalink] New post   20 Jan 2021, 04:10
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Since the area of square y is 4 shouldn't this mean (length(y))^2= 4 which means length(y)=2 so wouldn't the area of triangle be 1/2*1*2=1 ?

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Re: In the figure above, the areas of square regions X and Y are 1 and 4, [#permalink] New post   20 Jan 2021, 04:19
let Sx is the side of square X and SY the side of square y => Sx =sqrt (1) =1 & Sy= Sqrt(4)=2 => triangle surface = (Sx*Sy)/2= 1.
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Re: In the figure above, the areas of square regions X and Y are 1 and 4, [#permalink] New post   20 Jan 2021, 04:28
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The area of Triangle \( X\) is 1 and of Triangle \(Y\) is 4. This means that the sides of triangle \(X\) is \(1\) and triangle \(Y\) is \(2\).

Now one side of \(X\) forms the base of the triangular region and one side of \(Y\) forms the height of the triangular region.

Therefore, the area is \(\frac{1}{2}*b*h\)= \(\frac{1}{2}*1*2 = 1\).

Therefore, the OA is B.
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Re: In the figure above, the areas of square regions X and Y are 1 and 4, [#permalink] New post   20 Jan 2021, 09:59
It is a right angled triangle, with base = Sqrt(1)= 1 and height = Sqrt(4)=2

Area of a triangle = 1/2 * base * height = 1/2 *1 *2 = 1

So, I think B. :)
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Re: In the figure above, the areas of square regions X and Y are 1 and 4, [#permalink] New post   21 Jan 2021, 00:46
In the figure above, the areas of square regions X and Y are 1 and 4, respectively. What is the area of the triangular region?

Height of triangle = root 4 = 2
Base of triangle = root 1 = 1

Area of triangle = 1/2*2*1 = 1

Option B

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Re: In the figure above, the areas of square regions X and Y are 1 and 4, [#permalink]
21 Jan 2021, 00:46
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