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If N = 255 is the lowest of a set of 23 consecutive multiples of 15,

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Bunuel
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If N = 255 is the lowest of a set of 23 consecutive multiples of 15, [#permalink] New post   26 Oct 2016, 06:39
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If N = 255 is the lowest of a set of 23 consecutive multiples of 15, what is the range of this set?

(A) 315
(B) 330
(C) 345
(D) 360
(E) 375
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Re: If N = 255 is the lowest of a set of 23 consecutive multiples of 15, [#permalink] New post   26 Oct 2016, 10:30
N=255
255/15 = 17 ---> 17*15 and 17 is the lowest multiple of the 23 consecutive multiples
17+(23-1)= 39
39*15=585 - 17*15= 330

Hope its correct :D
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Re: If N = 255 is the lowest of a set of 23 consecutive multiples of 15, [#permalink] New post   26 Oct 2016, 11:00
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Highest = 225+(23-1)15

=225+22*15

Highest-Lowest = 225+22*15 - 225

= 330

B


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Re: If N = 255 is the lowest of a set of 23 consecutive multiples of 15, [#permalink] New post   26 Oct 2016, 11:11
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15*22=330. That is the difference between the first and last term. B
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Re: If N = 255 is the lowest of a set of 23 consecutive multiples of 15, [#permalink] New post   14 Apr 2019, 10:28
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Bunuel wrote:
If N = 255 is the lowest of a set of 23 consecutive multiples of 15, what is the range of this set?

(A) 315
(B) 330
(C) 345
(D) 360
(E) 375


series will be
1st term ; 255
2nd term 255+15,
3rd term 255+30...
so 23rd term = 255+(15*22) ; 585
so range = 585-255 ; 330
IMO B
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Re: If N = 255 is the lowest of a set of 23 consecutive multiples of 15, [#permalink] New post   22 Jan 2021, 18:14
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Re: If N = 255 is the lowest of a set of 23 consecutive multiples of 15, [#permalink]
22 Jan 2021, 18:14
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