If two integers x, y (x>y) are selected from -10 to 9 (inclusive), how

Since x>y
let us first choose y
then , we will choose x . because x is greater than y
Our choice of numbers are
-9 -8 -7 -6 ............................... 9 = total 9-(-10)+1 = 20 numbers

Now for every y that we choose ,x will always be to the right of y in the number line because x is greater

So we start from the left ,
If y = -9 , x can be chosen from 19 number in the right = > 19C1 = 19 ways
IF y= -8 , x can be chosen from 18 number in the right = > 18C1 = 18 ways
If y = -7 , x can be chosen from 17 number in the right = > 17C1 = 17 ways
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If y = 8 , x can be chosen from 1 number in the right = >only 9 Left =1 way
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Total = 19+18+17+..........................................1 = n(n+1)/2=(19.20)/2 = 190

Hence the answer is (C)