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Is y>y? (1) y < x z (2) z > x

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Bunuel
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Is y>y? (1) y < x z (2) z > x [#permalink] New post   20 Apr 2021, 01:30
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00:00
A
B
C
D
E

Difficulty:

5% (low)

Question Stats:

92% (00:50) correct 8% (00:47) wrong based on 60 sessions
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Is −y>y?

(1) y < x − z

(2) z > x
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C
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Bunuel
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Is y>y? (1) y < x z (2) z > x [#permalink] New post   21 Apr 2021, 01:15
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Is -y>y?

Is -y > y?
Is 0 > 2y?
Is y < 0?

(1) y < x − z. Not sufficient.

(2) z > x. Not sufficient.

(1)+(2) Subtract 2 from 1 (we can do that since the signs are in opposite direction):
y - z < (x - z) -x;
y - z < -z;
y < 0.
Sufficient.

Answer: C.
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chetan2u
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Re: Is y>y? (1) y < x z (2) z > x [#permalink] New post   20 Apr 2021, 01:58
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Bunuel wrote:
Is −y>y?

(1) y < x − z

(2) z > x


Project DS Butler Data Sufficiency (DS3)


For DS butler Questions Click Here



\(-y>y.......2y<0......y<0\)

So the question has now become: Is y<0?

1) \(y<x-z\)
Nothing about x and z.
If x-z>0, then no
If x-z<0, then yes

2)z>x or x-z<0
Nothing about y


Combined
x-z<0 and y<x-z
So \(y<x-z<0\)
Sufficient


C
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Re: Is y>y? (1) y < x z (2) z > x [#permalink] New post   20 Apr 2021, 04:57
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Bunuel wrote:
Is −y>y?

(1) y < x − z

(2) z > x


Project DS Butler Data Sufficiency (DS3)


For DS butler Questions Click Here


IMO answer is option C

We have to find is -y>y or y<-y or y+y= 2y<0?
or we have to find the sign of y

State 1 : y<x-z
y could be 0 , +ve or -ve . No definite answer

State 2 : x<z , nothing about y . SO insuff

When we combine both ,
x-z>y and z>x

lets plugin values, z=5 , x=3 so, 3-5>y and -2>y that means y is -ve and with a larger magnitude than -2.
therefore, from the quesion, 2*y <0 or 2*-y <0 . we have a definite No with C .
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Re: Is y>y? (1) y < x z (2) z > x [#permalink] New post   20 Apr 2021, 06:18
Is −y>y?

(1) y < x − z

(2) z > x

Statement 1
we have no idea about X and Z so we can not say anything about Y
Insufficient

Statement 2

Again we have no idea about Y
Insufficient

Combining 1 and 2
z > x
0>Z-X , Z - X is less than zero
We can say that Y is less than 0
and since Y is less than 0 we can conclude that -Y>Y
Sufficient
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Re: Is y>y? (1) y < x z (2) z > x [#permalink] New post   20 Apr 2021, 07:57
Is −y>y?
or 2y<0 or y<0

Statement 1: y < x − z
Not sufficient


Statement 2: z > x
No info about y; Hence, Not sufficient

Combined :
z>x or x-z<0 and y<x-z so, y<0

Hence, Sufficient

C is the answer
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Re: Is y>y? (1) y < x z (2) z > x [#permalink] New post   20 Apr 2021, 09:27
Is −y>y?

means is y -ve?

(1) y < x − z
y may or may not be -ve
Not sufficient

(2) z > x
no information about y
Not sufficient

Statement 1 & 2 combined
y < x − z & z > x so y is -ve
Sufficient

IMO C
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Re: Is y>y? (1) y < x z (2) z > x [#permalink] New post   20 Apr 2021, 09:52
Is −y>y? or, y<0?

Stat1: y < x − z, we have no idea of x and z. Not sufficient.

Stat2: z > x, we have no relation with y. Not sufficient.

Combining both, y< x-z <0. Sufficient.

So, I think C. :)
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Re: Is y>y? (1) y < x z (2) z > x [#permalink] New post   20 Apr 2021, 13:15
Is −y>y?

(1) y < x − z
We know nothing about x and z. Insufficient.

(2) z > x
Doesn't help reach an answer. Insufficient.

Combining 1 & 2
z>x this imples that x-z is always negative
Because y<x-z, y is always negative

And, negative of a negative number is positive, ie
-(-y)>-y

Yes. Ans C
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Re: Is y>y? (1) y < x z (2) z > x [#permalink] New post   20 Apr 2021, 20:24
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Is −y>y?

i.e is y <0 ?

(1) y < x − z

No idea about x and z .. Not Sufficient ..

(2) z > x


No idea about x and z .. Not Sufficient ..

Combining both ..

y < x − z => y <0 .. So y is negative ..Sufficient
Ans C
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Re: Is y>y? (1) y < x z (2) z > x [#permalink]
20 Apr 2021, 20:24
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Bunuel
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