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Re: A grocery store stocker whose hourly wage was increased by 50 percent [#permalink]
Bunuel wrote:
A grocery store stocker whose hourly wage was increased by 50 percent decided to reduce the number of hours worked per week so that his total weekly income would remain unchanged. By approximately what percent should the number of hours worked be reduced?

A. 12.5%
B. 20%
C. 25%
D. 33.33%
E. 66.67%
Attachment:
Hourly Wage.PNG
Hourly Wage.PNG [ 2.71 KiB | Viewed 2496 times ]
\(\frac{100}{15} = 6.67\)

Thus, percentage reduction in hours required is 33.33%, answer will be (E)
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A grocery store stocker whose hourly wage was increased by 50 percent [#permalink]
Abhishek009 wrote:
Bunuel wrote:
A grocery store stocker whose hourly wage was increased by 50 percent decided to reduce the number of hours worked per week so that his total weekly income would remain unchanged. By approximately what percent should the number of hours worked be reduced?

A. 12.5%
B. 20%
C. 25%
D. 33.33%
E. 66.67%
Attachment:
Hourly Wage.PNG
\(\frac{100}{15} = 6.67\)

Thus, percentage reduction in hours required is 33.33%, answer will be (E)


Hi Abishek, I think you mean the answer is (D) 33.33%

The numbers of hours worked reduced from 10 to 6.67 = 33.33% reduction, (D).

Originally posted by exc4libur on 28 Dec 2017, 17:16.
Last edited by exc4libur on 29 Dec 2017, 03:10, edited 1 time in total.
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A grocery store stocker whose hourly wage was increased by 50 percent [#permalink]
Expert Reply
Bunuel wrote:
A grocery store stocker whose hourly wage was increased by 50 percent decided to reduce the number of hours worked per week so that his total weekly income would remain unchanged. By approximately what percent should the number of hours worked be reduced?

A. 12.5%
B. 20%
C. 25%
D. 33.33%
E. 66.67%

Percent increase and percent decrease are inversely proportional when the original value is constant (or when returning to the original is the goal).

When there is a percent increase and decrease problem and the original is constant or sought after:

1) Find the fraction for the percent increase or decrease;

2) Flip the fraction;

3) If a percent increase is needed as offset, subtract the flipped fraction FROM 1. Change the decimal to a percent. Done. OR

4) If a percent decrease is needed as offset, subtract 1 from the flipped fraction. Change the decimal to a percent. Done.

Here, we have a 50 percent increase in weekly wage.

The worker wants to maintain the same weekly pay.

By what percent must he reduce his number of hours worked?

1) Fraction: A 50 percent increase = \(1.5 = 1 \frac{1}{2} = \frac{3}{2}\)

2) Flip that fraction: \(\frac{3}{2} --> \frac{2}{3}\)

3 ) Subtract from 1: \((1 - \frac{2}{3}) = \frac{1}{3} = .3333 \approx{33.33}\) % is the percent by which he must decrease his hours to maintain his original weekly pay.

Answer D

To offset a percent increase: (1 - fractional inverse of the increase)
To offset a percent decrease: (fractional inverse of the decrease - 1)
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Re: A grocery store stocker whose hourly wage was increased by 50 percent [#permalink]
Bunuel wrote:
A grocery store stocker whose hourly wage was increased by 50 percent decided to reduce the number of hours worked per week so that his total weekly income would remain unchanged. By approximately what percent should the number of hours worked be reduced?

A. 12.5%
B. 20%
C. 25%
D. 33.33%
E. 66.67%


let the weekly Wage be W and total number of hours worked = H.
Lets say that the stocker reduced his weekly working hours by x.
So, in order to keep the total wages same
=> W * H = 1.5W *(H-x)
=> H= 1.5H -1.5x
=> 0.5H = 1.5x
=> x = 1/3 = 0.3333 = 33.33%
Hence, D
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Re: A grocery store stocker whose hourly wage was increased by 50 percent [#permalink]
generis wrote:
Bunuel wrote:
A grocery store stocker whose hourly wage was increased by 50 percent decided to reduce the number of hours worked per week so that his total weekly income would remain unchanged. By approximately what percent should the number of hours worked be reduced?

A. 12.5%
B. 20%
C. 25%
D. 33.33%
E. 66.67%

Percent increase and percent decrease are inversely proportional when the original value is constant (or when returning to the original is the goal).

When there is a percent increase and decrease problem and the original is constant or sought after:

1) Find the fraction for the percent increase or decrease;

2) Flip the fraction;

3) If a percent increase is needed as offset, subtract the flipped fraction FROM 1. Change the decimal to a percent. Done. OR

4) If a percent decrease is needed as offset, subtract 1 from the flipped fraction. Change the decimal to a percent. Done.

Here, we have a 50 percent increase in weekly wage.

The worker wants to maintain the same weekly pay.

By what percent must he reduce his number of hours worked?

1) Fraction: A 50 percent increase = \(1.5 = 1 \frac{1}{2} = \frac{3}{2}\)

2) Flip that fraction: \(\frac{3}{2} --> \frac{2}{3}\)

3 ) Subtract from 1: \((1 - \frac{2}{3}) = \frac{1}{3} = .3333 \approx{33.33}\) % is the percent by which he must decrease his hours to maintain his original weekly pay.

Answer D

To offset a percent increase: (1 - fractional inverse of the increase)
To offset a percent decrease: (fractional inverse of the decrease - 1)



i directly considered 2/3 =66%
should have considered change - makes sense to subtract from 1

Thanks!!
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Re: A grocery store stocker whose hourly wage was increased by 50 percent [#permalink]
We can use the % change formula for a quick solve

Old value = 150% or \frac{3}{2 }x
New Value = x

therefore: \((x-\frac{3}{2}) \frac{2}{3}= \frac{(2-3)}{3} (\frac{2}{3}) = -\frac{1}{3}\)

Answer D
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Re: A grocery store stocker whose hourly wage was increased by 50 percent [#permalink]
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