The centre of the circle passing through the points (0, 0), (1, 1) an

Can you practically draw a circle passing through all the three points with center option B. It can't even be practical.

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Edited the typo in the stem. Thank you!

Asked: The centre of the circle passing through the points (0, 0), (1, 1) and (-1, 1) is

Let the equation of the circle be
(x-a)^2 + (y-b)^2 = r^2
where (a, b) is the centre of the circle and r is the radius of the same circle.

Since the circle passes through the points (0, 0), (1, 1) and (-1, 1) , these points should satisfy the equation of the circle

Point (0,0)
(0-a)^2 + (0-b)^2 = r^2
a^2 + b^2 = r^2

Point (1,1)
(1-a)^2 + (1-b)^2 = r^2
a^2 -2a + 1+ b^2 -2b + 1= r^2
Since a^2 + b^2 = r^2
a + b = 1

Point (-1,1)
(-1-a)^2 + (1-b)^2 = r^2
a^2 +2a + 1+ b^2 -2b + 1= r^2
Since a^2 + b^2 = r^2
b - a = 1

Since
a + b = 1 &
b - a = 1
b = 1; a= 0

Center of the circle = (0,1)

IMO B

Got it now. Thanks.