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Re: Brian ate 1/3, and Suzy ate some fraction of the cookies, and then Rac [#permalink]
Since we are discussing fractions, so sum of all the fractions will be equal to 1, as 1 is complete fraction.

Let Suzie had x fraction of the cookies
Brian ate 1/3 of the cookies
Rachel ate 1/2 (1-1/3-x) of the cookies
The left amount of cookies are 1/6

Hence the equation is
1/3 + x + 1/2(1-1/3 -x) + 1/6 = 1

1/3+ x + 1/2 -1/6 - x/2 +1/6 =1

5/6 + x/2 = 1

X/2 = 1/6

X=1/3

Ans is C

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Re: Brian ate 1/3, and Suzy ate some fraction of the cookies, and then Rac [#permalink]
Expert Reply
Let the total cookies were 36 [Take number which is divisible by 3, 2, and 6]

Brian: \(\frac{1}{3} * 36 = 12\)

Let's say Suzy has eaten the same number of cookies that Brian has eaten = 12

Remaining: 36 - (12 + 12) = 12

Rachel ate \(\frac{1}{2}\) of remaining(12) = \(\frac{1}{2} * 12 = 6\)

The cookies left at the end are 6 which is \(\frac{1}{6}\) of 36.

Hence, Suzy ate \(\frac{1}{3}\) of the cookies.

Answer C


Another method:

Brian + Suzy = \(\frac{1}{3} + \frac{1}{3} = \frac{2}{3}\)

=> Remaining: \(\frac{1}{3}\)

=> Rachel: \(\frac{1}{2} * \frac{1}{3} = \frac{1}{6} \)

=> Left out: \(\frac{1}{3} - \frac{1}{6} = \frac{1}{6}\)

Answer C
GMAT Club Bot
Re: Brian ate 1/3, and Suzy ate some fraction of the cookies, and then Rac [#permalink]
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