enigma123 wrote:
Of all the attendees at a dinner party, 40% were women. If each attendee arrived at a party either alone of with another attendee of the opposite sex, what percentage of the total number of attendees arrived at the party alone?
1. 50% of the male attendees arrived with a woman.
2. 25% of the attendes arriving alone were women.
This is how I am trying to solve this. Can someone please explain where I am getting it wrong ?
Considering statement 1
Solo Pairs Total
Men 30 30 60
Women 10 30 40
Total 40 60 100
If 30 men come in pairs then they have to be paired with 30 women. And therefore total people arrived solo are 40 and therefore this statement is sufficient.
Considering Statement 2 --> I am really struggling to solve this.
You got statement 1 so I will ignore that.
Statement 2: 25% of the attendes arriving alone were women.
To make calculations easier, lets assume that total number of people is 100. Then total number of women = 40 and total number of men = 60
Say, the number of alone women = x
Since this is 25% of total alone people, 3x is the number of alone men.
Now, total number of women with men = 40 - x
Then total number of men with women = 40 - x
(40-x)*2 + x + 3x = 100
x = 10
Women arriving alone = 10. men arriving alone = 30
% of people arriving alone = 40%
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