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A large ship moving at 14 mph in the river has an investigator cater

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A large ship moving at 14 mph in the river has an investigator cater [#permalink] New post   26 Sep 2021, 05:07
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A large ship moving at 14 mph in the river has an investigator cater swimming beside it. Investigator cater sets out to survey 70 miles downstream in the direction that the ship is headed. If the cater's speed is 28 mph, how much time will the cater spend surveying and coming back to the ship?

A. 2 hours 30 minutes
B. 2 hours 45 minutes
C. 3 hours 15 minutes
D. 3 hours 20 minutes
E. 3 hours 40 minutes
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D
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Re: A large ship moving at 14 mph in the river has an investigator cater [#permalink] New post   26 Sep 2021, 11:20
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sherxon wrote:
A large ship moving at 14 mph in the river has an investigator cater swimming beside it. Investigator cater sets out to survey 70 miles downstream in the direction that the ship is headed. If the cater's speed is 28 mph, how much time will the cater spend surveying and coming back to the ship?

A. 2 hours 30 minutes
B. 2 hours 45 minutes
C. 3 hours 15 minutes
D. 3 hours 20 minutes
E. 3 hours 40 minutes



I. Investigator cater ?? : Something say A
@ 28 mph, it will travel 70 miles in 2.5 hours or 2 hours and 30 minutes.

II. Ship, say B
In 2.5 hours, B has also traveled 14*2.5 or 35 miles 14 mph.

Distance between A and B is 70-35 or 35 miles.

When both travel towards each other, combined speed = 14+28 = 42 mph.
They will cover 35 miles in \(\frac{35}{42}*60=50\) minutes.

Total 2 hour 30 minutes + 50 minutes = 3 hours 20 minutes.


D
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Re: A large ship moving at 14 mph in the river has an investigator cater [#permalink] New post   26 Sep 2021, 11:35
sherxon wrote:
A large ship moving at 14 mph in the river has an investigator cater swimming beside it. Investigator cater sets out to survey 70 miles downstream in the direction that the ship is headed. If the cater's speed is 28 mph, how much time will the cater spend surveying and coming back to the ship?

A. 2 hours 30 minutes
B. 2 hours 45 minutes
C. 3 hours 15 minutes
D. 3 hours 20 minutes
E. 3 hours 40 minutes


total time it will take for the Cater to cover 70 miles ;
70/28 ; 2.5 hrs ; 2hrs 30 mins
in that time ship would have covered 17*2.5 ; 35 miles
distance left between ship & cater is 35 miles
relative speed opposite direction ; 14+28 ; 42 mph
time it would take to meet ; 35/42 ; .83*60; 50 mins
total time Cater spent ; 2 hrs : 30+50 ; 2hrs :80 mins ; or 3 hrs 20 mins
option D
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A large ship moving at 14 mph in the river has an investigator cater [#permalink] New post   28 Sep 2021, 22:17
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The scout vessel travels 70 miles downstream, turns back and meets the larger vessel. The sum of the distances covered by the two vessels during the exercise is 70*2=140 miles of which the larger vessel covers one-third and the scout vessel two-third. Distance covered by the scout vessel is 140*(2/3) and the time taken is 140*(2/3)/28 = 10/3 hrs.
ANS: d
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A large ship moving at 14 mph in the river has an investigator cater [#permalink]
28 Sep 2021, 22:17
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