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Re: If a,b and c are all positive integers satisfying a*b*c= 7(a+b+c), wha [#permalink]
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a*b*c= 7(a+b+c)

So one of a,b and c must be a multiple of 7. Since we have to minimize a+b+c, one of them is equal to 7(minimum positive multple of 7).

Consider c=7

a*b=a+b+7

a*b-a-b= 7

a*b-a-b+1 = 7+1

a(b-1)-1(b-1)=8

(a-1)(b-1) = 1*8 or 2*4

a=2 and b=9 or a=3 and b=5

To minimize a+b+c, consider 2nd case; a=3 and b=5.


KeyurJoshi wrote:
Is there any other way besides brute force method for this problem?
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Re: If a,b and c are all positive integers satisfying a*b*c= 7(a+b+c), wha [#permalink]
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a*b*c=7(a+b+c) in this substitute option, will get easily answer.
Lets choose option A=12
7(a+b+c)=7*12=84 make a factors of 84 =4*3*7
it's not equal to a+b+c=12

Now choose option B=15
7(a+b+c)=7*15=105 make a factors of 105
105=3*5*7
a*b*c=7(a+b+c)
3*5*7=7(3+5+7)

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Re: If a,b and c are all positive integers satisfying a*b*c= 7(a+b+c), wha [#permalink]
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Re: If a,b and c are all positive integers satisfying a*b*c= 7(a+b+c), wha [#permalink]
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