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Re: (2+2 * sqrt (6) )/2 [#permalink]
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(2 + 2(root)6)/2 = (2/2) + (2(root6)/2 = 1 + root 6 which is answer option C.
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Re: (2+2 * sqrt (6) )/2 [#permalink]
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Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

\(\frac{2+2\sqrt{6}}{2}=\)

(A) \(\sqrt{6}\)
(B) \(2\sqrt{6}\)
(C) \(1+\sqrt{6}\)
(D) \(1+2\sqrt{6}\)
(E) \(2+\sqrt{6}\)

Problem Solving
Question: 50
Category: Arithmetic Operations on radical expressions
Page: 68
Difficulty: 600


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\(\frac{2*(1+\sqrt{6})}{2}=1+\sqrt{6}\)
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Re: (2+2 * sqrt (6) )/2 [#permalink]
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Since 2 is a common factor in numerator and denominator , so taking 2 from each component of numerator and cancelling it with denominator.
(2+2*6^1/2)/2
=[2(1+6^1/2)]/2
=(2/2)(1+6^1/2)
=1+6^1/2

So the answer is (C)
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Re: (2+2 * sqrt (6) )/2 [#permalink]
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Taking the common number 2 from numerator gives us the result 1+\sqrt{6}; {2 gets canceled out}

Ans is (C)
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Re: (2+2 * sqrt (6) )/2 [#permalink]
Can anyone explain to me why this is incorrect?

1) multiple both sides of expression by 2
2) subtracting 2 from both sides
3) leaves you with 2squareroot6

Thanks
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Re: (2+2 * sqrt (6) )/2 [#permalink]
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Bunuel wrote:

\(\frac{2+2\sqrt{6}}{2}=\)

(A) \(\sqrt{6}\)
(B) \(2\sqrt{6}\)
(C) \(1+\sqrt{6}\)
(D) \(1+2\sqrt{6}\)
(E) \(2+\sqrt{6}\)
Quote:

modernx wrote:
Can anyone explain to me why this is incorrect?

1) multiple both sides of expression by 2
2) subtracting 2 from both sides
3) leaves you with 2squareroot6

Thanks

modernx , I think you must have assumed that RHS of equation = 1. It doesn't say that. So the best we can do is to simplify the fraction.

Your math, I think:

\(\frac{2+2\sqrt{6}}{2}=\)

\(\frac{2+2\sqrt{6}}{2} = 1\) (NO) -
Multiply by 2 to clear the fraction

\(2+2\sqrt{6} = 2\)
Subtract 2 from both

\(2\sqrt{6} = 0\) (NO)

Look at your statement #1. . . "both sides of the equation." There is not a right hand side value. . . It's easy to do when you are in a hurry or tired.

You cannot assume that the right hand side equals one. Hope that helps. :-)
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Re: (2+2 * sqrt (6) )/2 [#permalink]
modernx wrote:
Can anyone explain to me why this is incorrect?

1) multiple both sides of expression by 2
2) subtracting 2 from both sides
3) leaves you with 2squareroot6

Thanks
[/quote][/quote]
, I think you must have assumed that RHS of equation = 1. It doesn't say that. So the best we can do is to simplify the fraction.

Your math, I think:

\(\frac{2+2\sqrt{6}}{2}=\)

\(\frac{2+2\sqrt{6}}{2} = 1\) (NO) -
Multiply by 2 to clear the fraction

\(2+2\sqrt{6} = 2\)
Subtract 2 from both

\(2\sqrt{6} = 0\) (NO)

Look at your statement #1. . . "both sides of the equation." There is not a right hand side value. . . It's easy to do when you are in a hurry or tired.

You cannot assume that the right hand side equals one. Hope that helps. :-)[/quote]

Thanks for the clear explanation :)
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Re: (2+2 * sqrt (6) )/2 [#permalink]
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Quote:

\(\frac{2+2\sqrt{6}}{2}=\)

(A) \(\sqrt{6}\)
(B) \(2\sqrt{6}\)
(C) \(1+\sqrt{6}\)
(D) \(1+2\sqrt{6}\)
(E) \(2+\sqrt{6}\)


Distributing the 2 in the denominator, we have:

2/2 + (2√6)/2 = 1 + √6

Answer: C
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Re: (2+2 * sqrt (6) )/2 [#permalink]
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Who cannot solve this question should stay at home... lol
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Re: (2+2 * sqrt (6) )/2 [#permalink]
Expert Reply
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Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

\(\frac{2+2\sqrt{6}}{2}=\)

(A) \(\sqrt{6}\)
(B) \(2\sqrt{6}\)
(C) \(1+\sqrt{6}\)
(D) \(1+2\sqrt{6}\)
(E) \(2+\sqrt{6}\)


Here's the long solution so that students can see exactly what's happening algebraically.

\(\frac{2+2\sqrt{6}}{2}=\frac{2(1+\sqrt{6})}{2}\)

\(=\frac{2}{2} \times \frac{1+\sqrt{6}}{1}\)

\(=1 \times \frac{1+\sqrt{6}}{1}\)

\(=1+\sqrt{6}\)

Answer: C

Cheers,
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Re: (2+2 * sqrt (6) )/2 [#permalink]
Let’s take √ 6 = a

Now the equation is = ( 2 + 2a )/2

Separating the terms;

2/2 + 2a/2 = 1 + a
But a = √6

Thus option C, which is 1 + √6

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Re: (2+2 * sqrt (6) )/2 [#permalink]
Expert Reply
Take '2' common from the numerator and cancel '2' from the denominator.

We will get \(1 + \sqrt {6}\)

Answer C
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Re: (2+2 * sqrt (6) )/2 [#permalink]
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Re: (2+2 * sqrt (6) )/2 [#permalink]
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