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 Q48  V31
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Re: If 8 < k < 8, is k < 2 ? [#permalink]
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tirupatibalaji wrote:
Bunnel
what my process of thought was as follows:
S1 K^2 - 7k - 18 > 0
therefore (k+2)(k+9)>0
hence can also be written k>-2 or K>9, is it? so answer to question if K<-2 ? Answer is NO, therefore it is sufficient.

S2 1/k > 1/2
or it could be written as 0<K<2 so it is sufficient.


The red part is not correct: \((y+2)(y-9)>0\) --> \(y<-2\) or \(y>9\) --> as also given that \(-8<k<8\) then \(-8<k<-2\), so the answer to the question "is \(k<-2\)" will be YES. Sufficient.

Check this x2-4x-94661.html#p731476
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Re: If 8 < k < 8, is k < 2 ? [#permalink]
Thanks Brunnel. this has cleared my doubts. cheers!!

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Re: If 8 < k < 8, is k < 2 ? [#permalink]
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