NEW HERE? LEARN MORE
closeclose
Last visit was: 24 Apr 2024, 16:36 It is currently 24 Apr 2024, 16:36
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

DS-help required

User avatar
S
Marcab
Director
Director
Joined: 03 Feb 2011
Status:Retaking after 7 years
Posts: 864
Own Kudos [?]: 4468 [0]
Given Kudos: 221
Location: United States (NY)
Concentration: Finance, Economics
Schools: Simon '15 (M$)
GMAT 1: 720 Q49 V39
GPA: 3.75
Send PM
GMAT ToolKit User
DS-help required [#permalink] New post   21 Aug 2011, 10:25
is (k+1)(k+2)(k+3) divisible by 4?
a)k is divisible by 8
b)(k+1)/3 is odd

i dnt have any problem in statement 1 but in case of statement 2, i am confused b/w two ways.
one is-
if (k+1)/3 is odd, it means k+1 is odd...furthermore k is even
since even numbers comprises of 0 also, therefore the statement is insufficient

the second is-
k=2, (k+1)/3=(2+1)/3=1 which is odd
k=8, (k+1)/3=(8+1)/3=3 which is odd
and so on...considering this method, we can deduce k as either of {2, 8, 14, 20, 26...} for which the above expression is satisfied....


plz help

Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests for the latest questions.
Still interested? Check out the "Best Topics" block below for better discussion and related questions.
Thank you for understanding, and happy exploring!
User avatar
shashankp27
Intern
Intern
Joined: 25 Dec 2010
Posts: 39
Own Kudos [?]: 513 [0]
Given Kudos: 2
Send PM
Re: DS-help required [#permalink] New post   21 Aug 2011, 10:46
K+1/3 is odd ,
Take for instance K+1 = 9 , hence k+1/3 is odd (3) but k=8, hence 9*10*11 is NOT divisible by 4.
but if K+1=15 , k will be 14 and 15*16*17 is divisible by 4 . Hence 2 different answers , NOT sufficient.
User avatar
S
Marcab
Director
Director
Joined: 03 Feb 2011
Status:Retaking after 7 years
Posts: 864
Own Kudos [?]: 4468 [0]
Given Kudos: 221
Location: United States (NY)
Concentration: Finance, Economics
Schools: Simon '15 (M$)
GMAT 1: 720 Q49 V39
GPA: 3.75
Send PM
GMAT ToolKit User
Re: DS-help required [#permalink] New post   21 Aug 2011, 10:50
thnx man...came to knw where i was missing

Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests for the latest questions.
Still interested? Check out the "Best Topics" block above for better discussion and related questions.
Thank you for understanding, and happy exploring!
GMAT Club Bot
gmatclubot
Re: DS-help required [#permalink]
21 Aug 2011, 10:50
Moderator:
Bunuel
Math Expert
92900 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions