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Re: GMAT in 2 days, couple of questions [#permalink]
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Lanthane wrote:
Hi everyone,

There are a few problems I don't know to solve from GMAT Prep, could you please kindly help me? Test is on saturday and pressure is increasing :?

Thanks in advance !


Question 1:

The probability that red marble is chosen will be greater than the probability that white marble is chosen if there are more red marbles than white marbles.
So the question is just: Is r > w

Statement 1: r/(b + w) > w/(b + r)

Cross multiply to get r(b + r) > w(b + w) ... [(b + w) and (b + r) are definitely positive so cross multiplying is not a problem.]

Now, if r > w, (b + r) has to be greater than (b + w) and the inequality will hold.

If r were less than w, then (b + r) < (b + w) and the left side would have been smaller than the right side. Hence r cannot be less than w because it is given to us that the left side is greater than the right side.

So this implies that r must be greater than w. Sufficient.

Statement 2: b > r + w
But we cant compare r and w so not sufficient.

Answer (A).
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Re: GMAT in 2 days, couple of questions [#permalink]
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Question 3: x and y are not integers. Value of x is closest to which integer?

1. 4 is the integer closest to x+y
2. 1 is the integer closest to x-y

Statement 1: Since x+y is closest to 4,
3.5 < x+y < 4.5
No information about x alone.
Statement 2: Since x-y is closest to 1,
0.5 < x-y < 1.5
No information about x alone.

Using both together, add both the inequalities to get rid of y.
3.5 + .5 < x + y + x - y < 4.5 + 1.5
2 < x < 3
The value of x lies between 2 and 3 but we do not know whether it is closer to 2 (e.g. 2.3) or closer to 3 (e.g. 2.7). Hence not sufficient.

Answer E
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Re: GMAT in 2 days, couple of questions [#permalink]
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Question 4: Alice's take home pay.

I am putting down the Algebra solution (since you have the test tomorrow) though usually I would not do that. I would just skip to the options and plug them in to see what works.

Algebra: Say, her take home pay is $100 a month. She saves s every month and spends 100-s
At the end of the year, she saves 12s.
Given: 12s = 3(100-s)
s = 20
She saved 20/100 = 1/5 every month.

I would usually just try to plug in numbers. Say, if she saves 1/4 every month, she will have 12/4 = 3 at the end of the year. But this should be 3 times 3/4 which it isn't so 1/4 is too much. Go down a little.
Try 1/5. At the end of the year, she would have 12/5. She spends 4/5 every month. 12/5 is 3 times of 4/5 so got it!
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Re: GMAT in 2 days, couple of questions [#permalink]
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Question 5: s and t on number line

Make sure you read the question stem very very carefully tomorrow.
It says 's and t are two different numbers on the number line.'

Statement 1 tells you that distance between s and 0 is same as distance between t and 0. If s and t were on the same side of 0, they would be the same number. That is unacceptable. Hence they must be on different sides and one of them must be the negative of the other. Therefore, their sum must be 0.

Statement 2 just says that 0 is between s and t. It doesn't say it is right in the middle. s could be -2 and t could be 5 etc.



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