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# Pablo plays 3 rounds of a game, in which his chances of winn

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Senior Manager
Joined: 29 Jan 2011
Posts: 346

Kudos [?]: 244 [1], given: 87

Pablo plays 3 rounds of a game, in which his chances of winn [#permalink]

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22 Jun 2011, 01:34
1
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4
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Difficulty:

5% (low)

Question Stats:

72% (00:48) correct 28% (00:29) wrong based on 149 sessions

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Pablo plays 3 rounds of a game, in which his chances of winning each round are 1/3 ,1/6 , and 1/n, respectively. If n ≠ 0, what is the probability that Pablo wins the first two rounds, but loses the third?

A. 1/18n
B. (n-1)/18n
C. 1/2n
D. (n+2)/2n
E. (3n-2)/2n
[Reveal] Spoiler: OA

Last edited by Bunuel on 09 Sep 2013, 02:47, edited 1 time in total.
Renamed the topic, edited the question and the OA.

Kudos [?]: 244 [1], given: 87

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Kudos [?]: 592 [0], given: 36

Location: United States (IN)
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22 Jun 2011, 02:39
1/3 * 1/6 * (1-1/n)

= 1/18 * (n-1)/n

= (n-1)/18n

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Kudos [?]: 592 [0], given: 36

Director
Joined: 01 Feb 2011
Posts: 726

Kudos [?]: 143 [0], given: 42

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22 Jun 2011, 21:11
p(winning) = 1/3 * 1/6 * (n-1/n)

=(n-1)/(18n)

r u sure OA is C?

Kudos [?]: 143 [0], given: 42

Manager
Joined: 25 May 2011
Posts: 148

Kudos [?]: 74 [0], given: 71

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23 Dec 2011, 03:50
I also went to B. Why C?

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Manager
Joined: 26 Apr 2011
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27 Dec 2011, 04:57
I also got B ... why C?????? Please someone explain

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Manager
Joined: 11 Dec 2011
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Kudos [?]: 11 [0], given: 7

Location: Malaysia
Concentration: Nonprofit, Sustainability
GMAT 1: 730 Q49 V40
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28 Dec 2011, 03:13
Same here B as well, I don't understand why C

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Manager
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Kudos [?]: 69 [0], given: 6

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09 Jan 2012, 15:24
This is the quickest MGMAT problem I have ever solved.
1st, 2nt, no 3rd.

1/3 * 1/6 * (1 - 1/n) = (n-1)/18n
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Manager
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09 Jan 2012, 21:02

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Manager
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09 Jan 2012, 21:28
1
KUDOS
B.
Please explain the solution given in MGMAT for OA=C.
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Math Expert
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Re: Pablo plays 3 rounds of a game, in which his chances of winn [#permalink]

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09 Sep 2013, 02:49
1
KUDOS
Expert's post
siddhans wrote:
Pablo plays 3 rounds of a game, in which his chances of winning each round are 1/3 ,1/6 , and 1/n, respectively. If n ≠ 0, what is the probability that Pablo wins the first two rounds, but loses the third?

A. 1/18n
B. (n-1)/18n
C. 1/2n
D. (n+2)/2n
E. (3n-2)/2n

Edited the OA.

P = 1/3*1/6*(1-1/n) = (n-1)/18n.

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Re: Pablo plays 3 rounds of a game, in which his chances of winn [#permalink]

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28 Mar 2016, 08:17
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Kudos [?]: 273 [0], given: 0

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Re: Pablo plays 3 rounds of a game, in which his chances of winn [#permalink]

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02 Jun 2017, 20:57
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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Kudos [?]: 273 [0], given: 0

Re: Pablo plays 3 rounds of a game, in which his chances of winn   [#permalink] 02 Jun 2017, 20:57
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