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Hello guys,

Can someone explain how to get the answer for the following problem?

Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into a hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 10?

Can someone explain how to get the answer for the following problem?

Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into a hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 10?

or any combination that has those numbers in the first 6 picks, from there any number you get would add to 10 when added to the proper previously slip drawn.

Can someone explain how to get the answer for the following problem?

Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into a hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 10?

or any combination that has those numbers in the first 6 picks, from there any number you get would add to 10 when added to the proper previously slip drawn.

in worse case, it goes like this... 0, 1,2,3,4,5, so far six have been drawn and none of the two make to 10,
and the seventh one can be any (6,7,8,9) which added to the prvious one can make to 10.