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In an examination a student can answer in 56 ways. If the number of questions asked exceeds the number of question to be answered by 2, then how many questions were to be answered?
A) 6
B) 8
C) 4
D) 2
E) 5

In an examination a student can answer in 56 ways. If the number of questions asked exceeds the number of question to be answered by 2, then how many questions were to be answered? A) 6 B) 8 C) 4 D) 2 E) 5

If the number of questions is x, then the required number can be answered in xP(x-2) ways.

I remember seeing a similar question sometime back. The OE for that question was as follows

Let there be n questions. A person can answer a question in 2 ways by either answering it or not answering it.

Also we need to eliminate the possibility of not answering answering any of the questions. So the total number of ways to answer this whole test is (2^n) - 1. In that problem the number was 127. So 2^n -1 = 127 => n =7 But here the number is 56. Also Am not sure if permutation is the right way to go

In an examination a student can answer in 56 ways. If the number of questions asked exceeds the number of question to be answered by 2, then how many questions were to be answered? A) 6 B) 8 C) 4 D) 2 E) 5

If the number of questions is x, then the required number can be answered in xP(x-2) ways.