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Director
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15 Dec 2007, 18:05
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Guys,

Enclosed please find list of 55 different question with explanation. I got this from the GMATClub forum and found very impressive to learn most of the required commonly tested concepts.

I am returning back to the forum so that everyone can use it for hir/her benefit.

Amar

Please discuss specific questions in PS or DS subforums.

MODERATOR

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combinatroy_and_probability_132_914.doc [107.5 KiB]

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15 Dec 2007, 23:20
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thanks a lot, they are very helpful.
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27 Dec 2007, 23:00
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thanks for the stuff, its really helpful.
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04 Feb 2009, 00:20
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Thanks a lot, it is very helpfull!
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19 May 2009, 11:34
Thanks...for the great work
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24 Jun 2009, 05:22
This was really helpful. Thanks a lot dear!!, such inputs are of great help!!
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24 Jun 2009, 13:10
This is great. What's the difference b/w the two files?
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26 Jun 2009, 22:13
thx a lot.Looking for these for a long time.
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27 Jun 2009, 06:07
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29 Jun 2009, 15:46
Thank you so much for your kindness
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11 Jul 2009, 14:04
thanks a lot
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27 Jul 2009, 23:57
Thaks a lot
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28 Jul 2009, 05:18
thanks, i hope this is helpful.
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29 Jul 2009, 12:58
To the moderator

Can we include the download to the "Combinations, Permutations, and Probability - References" Sticky post.

Thanks
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29 Jul 2009, 19:31
I got more than half of the questions wrong in the first try
Seems I need a lot of practice.
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19 Aug 2009, 11:21
Amardeep,

Thank you so much for your very helpful post. I was in the middle of compiling a list of probablity questions myself when I realized that you had already done so.

Thanks again!
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13 Oct 2009, 11:03
Thanks alot!!
i needed something on this topic!
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14 Oct 2009, 07:21
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Thanks a lot friend, this can come in very handy.
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24 Oct 2009, 08:56
This is great! Thanks for posting this!
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25 Oct 2009, 21:03
I have a question regarding the #37 question and the answer given.

37. How many 5 digit numbers can be created if the following terms apply: the leftmost digit is even, the second is odd, the third is a non even prime and the fourth and fifth are two random digits not used before in the number?

a) 2520
b) 3150
c) 3360
d) 6000
e) 7500

37. The best answer is A.
The first digit has 4 options (2,4,6,8 and not 0), the second has 5 options (1,3,5,7,9) the third has 3 options (3,5,7 and not 2), the fourth has 7 options (10-3 used before) and the fifth has 6 options (10-4 used before). The total is 4*5*3*7*6=2520.

Now, it is not mentioned that a number cannot be repeated in for the 3rd digit. Say in the 2nd digit the number is 3 and so it is for the 3rd digit. The structure can be 233--, now for the 4th digit the option is 8 not 7.

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