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# PFA is m+z >0 1: m -3z >0 2: 4z -m >0

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Manager
Joined: 22 Sep 2008
Posts: 121

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PFA is m+z >0 1: m -3z >0 2: 4z -m >0 [#permalink]

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05 Oct 2008, 03:39
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

PFA

is m+z >0

1: m -3z >0
2: 4z -m >0
Attachments

m+z.JPG [ 57.21 KiB | Viewed 1154 times ]

Kudos [?]: 48 [0], given: 0

Retired Moderator
Joined: 05 Jul 2006
Posts: 1749

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Re: vs: is m+z >0 [#permalink]

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05 Oct 2008, 08:06
is m+z >0

1: m -3z >0
2: 4z -m >0

is m> -z

from 1

m>3z......insuff

from 2

4z>m = -4z<-m

z>0

however from 1 m>3z thus sure m>-z.........suff

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Manager
Joined: 27 Sep 2008
Posts: 76

Kudos [?]: 10 [0], given: 0

Re: vs: is m+z >0 [#permalink]

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05 Oct 2008, 10:54
solving for statements (1) or (2) won't do becuase you get either m > 3z or m < 4z

when you need ---> m < -z

but together (1) & (2)

m -3z > 0 & 4z -m > 0 ---> z > 0 and m > 0

sufficient

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Re: vs: is m+z >0   [#permalink] 05 Oct 2008, 10:54
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# PFA is m+z >0 1: m -3z >0 2: 4z -m >0

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