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Re: Point (P, Q) is in the coordinate plane. Is P > Q? [#permalink]
gmatophobia
can you explain statement 2 ? I am not able to understand.
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Re: Point (P, Q) is in the coordinate plane. Is P > Q? [#permalink]
AnujL wrote:
gmatophobia
can you explain statement 2 ? I am not able to understand.


Hey AnujL

Statement 2 mentions that "Point (P, Q) is above the line y = x + 1.". To understand this, let's plot the line y = x + 1 on the x-y plane.

Line x = y, has a positive slope and passes through the origin (shown in red).

Line y = x + 1, lies one unit above the line x. Therefore the line y = x + 1, will be parallel to the line y = x, and will lie at an distance of 1 unit from the line.

If the above explanation is confusing, we can also plot this line by finding the x-intercept and the y-intercept.

x-intercept of the line -

0 = x + 1

x = -1

So the line cuts the x-axis at (-1,0)

y-intercept of the line -

y = 0 + 1

y = 1

So the line cuts the y-axis at (0,1)

We can draw a line passing through these two points. The line is shown in green.

Statement 2 tells us that point (P, Q) is above the line y = x + 1. Hence point P lies in the region shaded in green.

Note: In this region, the value of y is always greater than the value of x+1 (i.e. y > x + 1)
Attachments

y gt x + 1.jpg
y gt x + 1.jpg [ 33.83 KiB | Viewed 729 times ]

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Re: Point (P, Q) is in the coordinate plane. Is P > Q? [#permalink]
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