How many two-digit whole numbers yield a remainder of 3 when divided

Answer = D) Four

Numbers giving remainder 3 when divided by 10 = 13, 23, 33, 43, 53, 63, 73, 83, 93

Numbers giving remainder 3 when divided by 4 = Alternate numbers (coloured in red) = 4

If we place p = 0, it will return x = 3 (Single digit number)

Yes.. missed on that... I have corrected the solution

The correct answer is D.

First Of all we could arrange every 2 digit number when we divide by 10 give us reminder 3 . It Is obvious that the number will have 3 in its unit digit

so we will have the list of numbers as follows : 13 , 23, 33, 43, 53, 63, 73, 83, and 93......

in this stage we should divide each number by 4 and see which of them yields reminder 3 after dividing by 4

we see here the first number (13) gives us reminder 1 so it is out the second number( 23) gives us reminder 3 so it is OK

the third number gives reminder 1 so out and if we continue this action we see the pattern will be repeat again one by one so the even members will give us reminder 3

if we count the even number we see here we have 23 , 43, 63, and 83 so we have 4 number and Option D is fit ...

How many two-digit whole numbers yield a remainder of 3 when divided by 10 and also yield a remainder of 3 when divided by 4?

A) One
B) Two
C) Three
D) Four
E) Five

lowest value of n=3
interval between possible values of n=lcm of divisors=20
let x=number of two-digit values of n
3+20x<100
20x<97
x<4.9
x=4
D

We need to determine how many two-digit whole numbers yield a remainder of 3 when divided by 10 and also yield a remainder of 3 when divided by 4. Let’s list out the numbers that have a remainder of 3 when divided by 10.

Remainder of 3 when divided by 10:

13, 23, 33, 43, 53, 63, 73, 83, 93

Of those numbers, only 23, 43, 63, and 83 leave a remainder of 3 when divided by 4.

Alternate Solution:

Note that for a number to yield a remainder of 3 when divided by 10, the unit digit must be 3. Note also that for a number to yield a remainder of 3 when divided by 4, three less than that number must be divisible by 4. Combining these two pieces of information, we need to look for two-digit numbers that are divisible by 4 and that have a units digit of zero. These numbers are 20, 40, 60, and 80. Therefore, 23, 43, 63, and 83 are the only two-digit numbers that yield a remainder of 3 when divided by 4 and by 10.

Answer: D

LCM of 10 and 4 is 20. The only 2-digit multiples of 20 are 20,40,60,80. The 2 digit numbers which when divided by 4 and 10 have remainder 3 are thus: 23, 43, 63, 83.

4 in all.

Answer is D.

take the lcm of 4 and 10. which is 20.

now take the first common number from both the patters 10k+3 and 4q+3, which is 3.

now common series is 20n+3 and we will get 0,23,43,63 and 83.

since we have been asked only 2 digit numbers, the answer is 4.

option D is the correct asnwer.

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