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If 0 < x < 7 and y < 9, then the lowest possible value for xy is

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Bunuel
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If 0 < x < 7 and y < 9, then the lowest possible value for xy is [#permalink] New post   29 Mar 2016, 02:55
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If 0 < x < 7 and y < 9, then the lowest possible value for xy is

A. between 60 and 70
B. between 0 and 60
C. 0
D. between 0 and -70
E. less than -70
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E
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Re: If 0 < x < 7 and y < 9, then the lowest possible value for xy is [#permalink] New post   29 Mar 2016, 04:23
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If 0 < x < 7 and y < 9, then the lowest possible value for xy is

A. between 60 and 70
B. between 0 and 60
C. 0
D. between 0 and -70
E. less than -70

Say y = -100 (y<9)
x = 6
So xy =-600 which is less than -70. Answer is E.
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rohit8865
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Re: If 0 < x < 7 and y < 9, then the lowest possible value for xy is [#permalink] New post   29 Mar 2016, 11:07
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Bunuel wrote:
If 0 < x < 7 and y < 9, then the lowest possible value for xy is

A. between 60 and 70
B. between 0 and 60
C. 0
D. between 0 and -70
E. less than -70


minimum possible value comes when one varible is +ve and another is -ve
Here a range for x is defined and minimum value for x could be 0.0000...1
and no range is defined for Y ..so Y could be any -ve value.say Y=-1000000......0
Making the best ans choice which is the most -ve.
Ans E.
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Re: If 0 < x < 7 and y < 9, then the lowest possible value for xy is [#permalink] New post   28 May 2017, 00:26
Bunuel wrote:
If 0 < x < 7 and y < 9, then the lowest possible value for xy is

A. between 60 and 70
B. between 0 and 60
C. 0
D. between 0 and -70
E. less than -70


0 < x < 7 , here the minimum value of x will be 1

y < 9 , minimum value will be any extreme number to the left (In the number line ) of 9 , which includes 0 and -ve numbers...

\(+ve * -ve = -ve number\)

So, the minimum value of xy will be a -ve integer...

Thus, the correct answer will be (E) less than -70
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Re: If 0 < x < 7 and y < 9, then the lowest possible value for xy is [#permalink] New post   10 Dec 2019, 13:34
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Hi All,

We're told that 0 < X < 9 and Y < 9. We're asked for the SMALLEST possible value of (X)(Y). This question is ultimately about Number Properties, so we can answer it in a number of different ways - including by TESTing VALUES or logic.

We know that X must be POSITIVE and Y can be positive (but less than 9), 0 or ANY negative. To make the product (X)(Y) as SMALL as possible, Y would have to be AS NEGATIVE AS POSSIBLE. Multiplying that type of extreme negative value by any positive value would lead to another extreme negative value (re: negative infinity).

Final Answer:
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E


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Re: If 0 < x < 7 and y < 9, then the lowest possible value for xy is [#permalink] New post   16 Dec 2020, 07:08
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Re: If 0 < x < 7 and y < 9, then the lowest possible value for xy is [#permalink]
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