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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
Doesn't 3 parts of white paint with 5 parts of black paint. play any role... plzz explain..im missing somewhere..

thanks
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
Thanks Bunuel.. Its crystal clear now.. now even ur 1st ans to this Q explains everything very clearly...
Thanks once again... +1...
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
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TheSituation wrote:
I've been banging my head against the wall on this one... someone please give me a simple straightforward solution and assurance that it was a very difficult question lol.

A certain shade of gray paint is obtained by mixing 3 parts of white paint with 5 parts of black paint. If 2 gallons of the mixture is needed and the individual colors can be purchased only in one-gallon or half- gallon cans, what is the least amount of paint, in gallons, that must be purchased in order to measure out the portions needed for the mixture?
(A) 2
(B) 2.5
(C) 3
(D) 3.5
(E) 4

OA:


white = 3/8
black = 5/8

Combine both and that equals 1 gallon

Multiply each by two to get 2 gallons

(3/8)*2 + (5/8)*2 = 2

(3/8)*2 = 6/8 = 3/4 = .75
(5/8)*2 = 10/8 = 5/4 = 1.25

You need .75 gallons of white but since it comes in 1/2 or 1 you need 1 gallon
You need 1.25 gallons of black but since it comes in 1/2 or 1 you need 1.5

1+1.5 = 2.5
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
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Bumping for review and further discussion*. Get a kudos point for an alternative solution!

*New project from GMAT Club!!! Check HERE

All DS Mixture Problems to practice: search.php?search_id=tag&tag_id=43
All PS Mixture Problems to practice: search.php?search_id=tag&tag_id=114
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
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Let one gallon be 80 liters. ( Assume smartly)

30 White +50 black = 80liters

According 2 question, we need 2 gallons i.e- 160 liters. ( multiply above equation with 2)

60W+100B=160 ltrs

Minimum gallons for 60W=1 ( 1 gallon =80 liters, 1/2=40 liters)
Minimum gallons for (80+20) B= 1+0.5=1.5
Total = 1+1.5=2.5

Ans. 2.5
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
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Given W:B = 3:5
That means say 3 gallons of white paint + 5 gallons of black paint = 8 gallons of paint mixture.
But we want least amount of white & black paints for minimum of 2 gallons of mixture, so lets reduce keeping same ratio,
1.5 : 2.5 gives 1.5 + 2.5 = 4 gallons of mixture, but we want only 2 gallons, lets further reduce
0.75: 1.25 gives 1+1.5 = 2.5 gallons of mixture. This looks ok, but lets reduce further just to be sure
0.375: 0.625 gives 0.5 + 1 = 1.5 gallons of mixture, thats less than 2 gallons of mixture, so not acceptable.
So correct ans is 2.5 gallons. B
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
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The mixture is made up of 3 parts white paint and 5 parts Black paint.
Hence total is 8 parts make 2 gallons of mixture.
8x = 2(gallons) ==> x = 1/4

White paint needed = 3* 1/4 =0.75. Minimum White paint needed = 1
Black Paint needed = 5* 1/4 = 1.25 Minimum Black Paint needed = 1.5

Hence Answer = 2.5. B
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
benmtchong wrote:
A certain shade of gray paint is obtained by mixing 3 parts of white paint with 5 parts of black paint. If 2 gallons of the mixture is needed and the individual colors can be purchased only in one gallon or half gallon cans, what is the least amount of paint, in gallons, that must be purchased in order to measure out the portions needed for the mixture?

A. 2
B. 2 1/2
C. 3
D. 3 1/2
E. 4


I don't like the wording of the question! There is a possibility of two solutions here..all depends o what exactly "measure out" means to say in the question..and some information that I find is missing in the question. It should be clearly stated that one can measure out exactly as much as wanted from any can(example, one can take out 0.75 liters from a 1 liter can, and so forth). In this case, 2.5 is the correct answer. But if such thing is not possible, then we would have to work exclusively with 0.5 and 1 liter cans only, in which case, 4 will be the answer. I'm not sure if my argument is ill-founded, but please, clarify. I request Bunuel to comment and also clarify, so I don't make such comprehension mistakes if I did so.
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
ShashankDave wrote:
benmtchong wrote:
A certain shade of gray paint is obtained by mixing 3 parts of white paint with 5 parts of black paint. If 2 gallons of the mixture is needed and the individual colors can be purchased only in one gallon or half gallon cans, what is the least amount of paint, in gallons, that must be purchased in order to measure out the portions needed for the mixture?

A. 2
B. 2 1/2
C. 3
D. 3 1/2
E. 4


I don't like the wording of the question! There is a possibility of two solutions here..all depends o what exactly "measure out" means to say in the question..and some information that I find is missing in the question. It should be clearly stated that one can measure out exactly as much as wanted from any can(example, one can take out 0.75 liters from a 1 liter can, and so forth). In this case, 2.5 is the correct answer. But if such thing is not possible, then we would have to work exclusively with 0.5 and 1 liter cans only, in which case, 4 will be the answer. I'm not sure if my argument is ill-founded, but please, clarify. I request Bunuel to comment and also clarify, so I don't make such comprehension mistakes if I did so.


I approached this question in the same way and made the same mistake. My assumption was that we would have to pour together the whole (1 or 1/2 gallon) cans so that we can get at least 2 liters of grey paint, which gives E as a result.
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
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Scyzo wrote:
ShashankDave wrote:
benmtchong wrote:
A certain shade of gray paint is obtained by mixing 3 parts of white paint with 5 parts of black paint. If 2 gallons of the mixture is needed and the individual colors can be purchased only in one gallon or half gallon cans, what is the least amount of paint, in gallons, that must be purchased in order to measure out the portions needed for the mixture?

A. 2
B. 2 1/2
C. 3
D. 3 1/2
E. 4


I don't like the wording of the question! There is a possibility of two solutions here..all depends o what exactly "measure out" means to say in the question..and some information that I find is missing in the question. It should be clearly stated that one can measure out exactly as much as wanted from any can(example, one can take out 0.75 liters from a 1 liter can, and so forth). In this case, 2.5 is the correct answer. But if such thing is not possible, then we would have to work exclusively with 0.5 and 1 liter cans only, in which case, 4 will be the answer. I'm not sure if my argument is ill-founded, but please, clarify. I request Bunuel to comment and also clarify, so I don't make such comprehension mistakes if I did so.


I approached this question in the same way and made the same mistake. My assumption was that we would have to pour together the whole (1 or 1/2 gallon) cans so that we can get at least 2 liters of grey paint, which gives E as a result.


Look at the last line of the question: what is the least amount of paint, in gallons, that must be purchased in order to measure out the portions needed for the mixture?

This clarifies that you need to find the least amount of paint that you need to buy to measure out the portions needed for 2 gallons mix.
Otherwise, it would have been mentioned that you need to use the whole can.
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
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benmtchong wrote:
A certain shade of gray paint is obtained by mixing 3 parts of white paint with 5 parts of black paint. If 2 gallons of the mixture is needed and the individual colors can be purchased only in one gallon or half gallon cans, what is the least amount of paint, in gallons, that must be purchased in order to measure out the portions needed for the mixture?

A. 2
B. 2 1/2
C. 3
D. 3 1/2
E. 4


We are given that a gray pain is obtained by mixing 3 parts of white paint with 5 parts of black paint. We are also given that the paint can be purchased in one- or half-gallon cans and that the total mixture is 2 gallons. We must determine the minimum number of gallons of paint of each color needed.

Our given ratio is:

w/b = 3/5 = 1.5/2.5 = 0.75/1.25

As we can see, we need to have 0.75 gallons of white paint and 1.25 gallons of black paint in order to have 2 gallons of the mixed (i.e., gray) paint. However, in order to have the 0.75 gallons of white paint, we need to purchase 1 gallon of white paint, and in order to have the 1.25 gallons of black paint, we need to purchase 1.5 gallons of black paint. Thus, we need to purchase a total of 2.5 gallons of paint.

Answer: B
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
benmtchong wrote:
A certain shade of gray paint is obtained by mixing 3 parts of white paint with 5 parts of black paint. If 2 gallons of the mixture is needed and the individual colors can be purchased only in one gallon or half gallon cans, what is the least amount of paint, in gallons, that must be purchased in order to measure out the portions needed for the mixture?


A. 2

B. \(2 \frac{1}{2}\)

C. 3

D. \(3 \frac{1}{2}\)

E. 4


We need 2*3/8 = .75 gallons of white and 1.25 gallons of black. Plug in the options. Start from C, 3 gallons. If we buy 1 gallon of white and 2 gallons of black, we can distribute but since more than half gallons of black paint will remain, we should buy 1 one gallon of black and another half gallon of black. So, total 2 and half gallons are needed.
B is the answer
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A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
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benmtchong wrote:
A certain shade of gray paint is obtained by mixing 3 parts of white paint with 5 parts of black paint. If 2 gallons of the mixture is needed and the individual colors can be purchased only in one gallon or half gallon cans, what is the least amount of paint, in gallons, that must be purchased in order to measure out the portions needed for the mixture?


A. 2

B. \(2 \frac{1}{2}\)

C. 3

D. \(3 \frac{1}{2}\)

E. 4


White: Black = 3:5, Total is 3+5=8

Required white paint=2*\(\frac{3}{8}\) \(= 0.75\)

Required Black paint= 2*\(\frac{5}{8}\) \(=1.25\)

Total = 0.75+1.25=2.5 or \(2 \frac{1}{2}\)

The Answer is B
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
Grey paint is obtained by mixing 3 part of White and 5 part of Black paint
say 1Gallon is G
if we mix 3G of white paint and 5G of black paint we get 8G of Grey paint
but we need only 2G of grey paint
so 2G of Grey paint = (3/4)G of white paint + (5/4)G of Black paint

but the white and black paint are available in 0.5G and 1G cans
and since we need to buy the least amount of paint
to get 3/4 G of white paint we need to buy 1G of white paint
and to get 5/4G of black paint we need to buy 3/2 G of black paint
total 2.5G of white and black paint
Answer: B
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
hi,



Bunuel

is this approach correct

2 gallons =5X + 3X

x=1/4

5(1/4) =1.25 so 1 can + half can

3(1/4)= 0.75 so 1 can


total 2 1/2
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
Whenever I see parts, i am more inclined to use fractions.

3/8 W + 5/8B = G

We need 2G

2*3/8 + 2*5/8 = 2G

6/8 W + 10/8 B

0.75W + 1.25 B

to cover 0.75 we need 1 Gallon

to cover 1.25 we need 1.5 Gallon

1 + 1.5 = 2.5

B!
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Re: A certain shade of gray paint is obtained by mixing 3 parts of white [#permalink]
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