Last visit was: 23 Apr 2024, 23:36 It is currently 23 Apr 2024, 23:36

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
User avatar
Retired Moderator
Joined: 25 Jul 2011
Posts: 299
Own Kudos [?]: 313 [1]
Given Kudos: 286
Location: India
Concentration: Strategy, General Management
GMAT 1: 730 Q50 V40
GRE 1: Q800 V800
GPA: 3
WE:Operations (Non-Profit and Government)
Send PM
CEO
CEO
Joined: 24 Jul 2011
Status: World Rank #4 MBA Admissions Consultant
Posts: 3187
Own Kudos [?]: 1585 [0]
Given Kudos: 33
GMAT 1: 780 Q51 V48
GRE 1: Q170 V170
Send PM
avatar
Intern
Intern
Joined: 15 Nov 2009
Posts: 4
Own Kudos [?]: 15 [0]
Given Kudos: 0
Location: Moscow, Russia
Send PM
avatar
Intern
Intern
Joined: 12 Feb 2011
Posts: 2
Own Kudos [?]: 4 [0]
Given Kudos: 4
Send PM
Re: GRE Weekly Challenge #3 [#permalink]
Answer B - Quantity B is greater.‎
‎|x – 5|=|5 – x|;‎
‎|a – b|=|b – a|;‎
As 5<x<10, then 0<|x – 5|<5 and 0<|5 – x|<5;‎
As a<0, b>0, then |a – b|=|b – a|=|a|+|b|;‎
‎|a|>0 and 5<|b|<10, then (|a|+|b|)>5;‎
Therefore, |x – 5| < |a – b|, (|x – 5| – |a – b|) < 0 and ‎
‎(|b – a| – |5 – x|) > 0, which means that‎
‎(|x – 5| – |a – b|) < (|b – a| – |5 – x|) for all a, b, x.‎
User avatar
Intern
Intern
Joined: 13 May 2011
Status:single
Posts: 13
Own Kudos [?]: 38 [0]
Given Kudos: 6
Location: India
Concentration: Entrepreneurship, Strategy
GPA: 3
WE:Manufacturing and Production (Other)
Send PM
Re: GRE Weekly Challenge #3 [#permalink]
Quantity B is greater.
A=|x-5|-|a-b|
= (x-5)-(-(a-b)

since x>5, so the mod will always open positive.
since a<b, |a-b| will always open negetive.

so A= x-5+a-b ............(i)

B=|b-a|-|5-x|
= (b-a)-(-(5-x)
same logic as above.

so B= b-a+5-x ...............(ii)

so A= -(B) ............... from (i) and (ii)
now,
numerical value of b-a is greater than 5 since 0 and 5 lies between a and b.
numerical value of 5-x is less than 5 since x lies between 5 and 10.
so, B is a positive quantity or A is a negetive quantity.

therefore, B>A
User avatar
Manager
Manager
Joined: 24 Nov 2010
Posts: 119
Own Kudos [?]: 247 [0]
Given Kudos: 7
Location: United States (CA)
Concentration: Technology, Entrepreneurship
Send PM
Re: GRE Weekly Challenge #3 [#permalink]
Ans B

Let |x-5| = |5-x| = c --> 0<c<5
Let |a - b| = |b - a| = d --> 5<d<infinity

A = |x – 5| – |a – b| = (0<c<5) - (5<d<infinity) = -ve
B = |b – a| – |5 – x| = (5<d<infinity) - (0<c<5) = +ve

therefore B is greater
avatar
Intern
Intern
Joined: 23 Aug 2011
Posts: 6
Own Kudos [?]: [0]
Given Kudos: 1
Send PM
Re: GRE Weekly Challenge #3 [#permalink]
Ans: D

The intervals is not equal so we can not determine !!
Joined: 31 Dec 1969
Own Kudos [?]: [0]
Given Kudos:
Concentration: Entrepreneurship, International Business
WE:Supply Chain Management (Energy and Utilities)
Re: GRE Weekly Challenge #3 [#permalink]
The correct answer is: B)Quantity B is greater.

Quantity A:

0 < |x-5| < 5

|a-b| > b ==> |a-b| > 5

==>
|x – 5| – |a – b| = (0 < |x-5| < 5) - (|a-b| > 5) <=== This expression is clearly smaller than 0

Quantity B:

|b – a| = b+|a| > 5

|5 – x| < 5 (since 5 < x < 10 )

==>
|b – a| – |5 – x| = ( b+|a| > 5) - (|5 – x| < 5) <=== This expression is clearly greater than 0

So quantity B is greater than quantity A.
avatar
Intern
Intern
Joined: 19 Jun 2011
Posts: 3
Own Kudos [?]: [0]
Given Kudos: 0
Send PM
Re: GRE Weekly Challenge #3 [#permalink]
Quantity B

|5-x|-->X varies from 5 to 10 therefore |5-x| varies from 0 to 5
|b-a|--> B varies from 5 to 10 and is greater then X ..and A is less than 0.Therefore |b-a| is either greater then 10 or greater than 5.Which means greater than 5 covers the entire range.
Hence ,|b-a|-|5-x| is always positive...(1)

Quantity A
Since x > 0 , |x-5| is the same range as |5-x| varying from 0 to 5
|a-b| again as |b-a| varies from 5 to 10
Hence . |b-a|-|5-x| is < 0 ....(2)

Therefore Clearly , Quantity B is greater then Quantity A.
avatar
Intern
Intern
Joined: 18 Sep 2011
Posts: 3
Own Kudos [?]: [0]
Given Kudos: 0
Send PM
Re: GRE Weekly Challenge #3 [#permalink]
ready to participage....
GMAT Club Bot
Re: GRE Weekly Challenge #3 [#permalink]

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne