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# Power Prep Question

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Intern
Joined: 12 Aug 2004
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03 Oct 2004, 22:29
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

can any one explain the answer
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Director
Joined: 16 Jun 2004
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04 Oct 2004, 01:07
For stem 1:
We can think of Two scenarios:
First scenario: S=(-3,-1,1,3,5). Here the mean = 5/5 = 1. Median =1
Second scenarion: S =(-3,-1,1,3,5,7). Here the mean = 12/6 = 2. Median =(1+3)/2 = 2. Same results. We can conclude that the avg = median. A firm Yes.

Thus, sufficient.

For stem 2:
Its given that the range is 2(n-1). Lets consider a 4 member set. We will then have the range as 2(4-1) =6. The set can be S= (1,0,0,7) which has Range = 6. The avg is not equal to Median here. The set can also be (0,3,3,6) again the range being 6. However, here, the avg = median. We cannot conclude that avg = median for sure with this stem. Thus Insufficient.

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Intern
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04 Oct 2004, 07:00
GREAT EXPLANATION!

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04 Oct 2004, 07:00
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