r19 wrote:
not able to understand why option 1 sufficient? can you explain with example?
Hey mate, see whether the below explanation helps.
Let the initial no of chocolates be N. Let the price per chocolate be P.
Initial revenue = NxP.
Given the increase in price is x% and decrease in the amount of chocolates sold is y%.
New revenue = [(100+x)/100] x [(100-y)/100] x N x P
Question: Whether the new revenue is more than the old revenue?
A) Given x=y.
If x=y=0
New revenue=Old revenue. There is no increase in revenue after the change so new revenue is not more than old revenue. So the answer for question asked is 'no'.
If x=y=Any value other than 0
The new revenue will be lesser than old revenue. So the answer for the question is again 'no'
Hence A is sufficient.
Cheers!