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Probabilty

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Senior Manager
Senior Manager
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Joined: 20 Feb 2008
Posts: 295

Kudos [?]: 50 [0], given: 0

Location: Bangalore, India
Schools: R1:Cornell, Yale, NYU. R2: Haas, MIT, Ross
Probabilty [#permalink]

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New post 16 May 2008, 13:17
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

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Senior Manager
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Joined: 19 Apr 2008
Posts: 314

Kudos [?]: 99 [0], given: 0

Re: Probabilty [#permalink]

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New post 16 May 2008, 14:05
ventivish wrote:
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E

head atleast 4 times = head exactly 4 times + head 5 times

if it is head 5 times probability is (0.6)^5 ; eliminate A, B,C -----------------I

now between D and E ,

5(0.6)^4(0.4) ; represent prob of head 4 times

if coin is tossed 5 times ,there are 5 different ways we can have exactly 4 heads and prob of tail exactly once would be 0.4 ,so we get 5(0.6)^4(0.4) --------------------------II

combining outcome of I and II we get E

Kudos [?]: 99 [0], given: 0

Senior Manager
Senior Manager
avatar
Joined: 20 Feb 2008
Posts: 295

Kudos [?]: 50 [0], given: 0

Location: Bangalore, India
Schools: R1:Cornell, Yale, NYU. R2: Haas, MIT, Ross
Re: Probabilty [#permalink]

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New post 16 May 2008, 15:20
Thank you, completely forgot about this formula that could be applied!!(Just read about Bernoulli's equation on one of the posts)

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Re: Probabilty   [#permalink] 16 May 2008, 15:20
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Probabilty

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