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This topic is locked. If you want to discuss this question please re-post it in the respective forum.

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The sum of the ages of 22 boys and 24 girls is 160.What is the sum of ages of one boy plus one girl, if all the boys are of the same age and all the girls are of the same age, and only full years are counted?

22B + 24G = 150. (B and G are integers) ==> 11B + 12G = 80. ==> 11(B+G) +G = 80 ==> B+G = (80-G) / 11. Since B and G are intergers, then B + G must be an integer ==> 80 - G must be a multiple of 11. This implies G is the reaminder left when 80 is divided by 11. Ie G = 3.

Substituting G in B +G we get (80 - 3) / 11 = 7 which is the ans.

We know from the answers that Y must be less than or equal to 8.

So, 22(X+Y) must be greater than or equal to 144, and less that 160. Only answer possible is 7. _____________________________ Consider KUDOS for good posts