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# ps: Chicken

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Senior Manager
Joined: 02 Feb 2004
Posts: 345
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20 May 2005, 16:37
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Senior Manager
Joined: 02 Feb 2004
Posts: 345
Followers: 1

Kudos [?]: 65 [0], given: 0

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20 May 2005, 17:49
gmat2me2 wrote:
Getting 300

Director
Joined: 18 Feb 2005
Posts: 670
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Kudos [?]: 6 [0], given: 0

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20 May 2005, 18:05
Let x be the chicken and y be the number of days

This could be solved by calculating the chicken-days (cos it is a constant if we closely observe)

(x-75)(y+20) = x*y; (when 75 chicken are sold)

(x+100)(y-15) = x*y;(when 100 chicken are bought)

Since the above 2 equations are same

we get x=5y;

Solve it you get y=60 and x=300
Senior Manager
Joined: 17 Apr 2005
Posts: 373
Location: India
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21 May 2005, 00:41
gmat2me2 wrote:
Let x be the chicken and y be the number of days

This could be solved by calculating the chicken-days (cos it is a constant if we closely observe)

(x-75)(y+20) = x*y; (when 75 chicken are sold)

(x+100)(y-15) = x*y;(when 100 chicken are bought)

Since the above 2 equations are same

we get x=5y;

Solve it you get y=60 and x=300

Got 300 too, but couldn't see any short cuts here.

HTMG
21 May 2005, 00:41
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