Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 24 May 2017, 14:08

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# PS-coordinates

Author Message
Manager
Joined: 05 Jul 2006
Posts: 197
Followers: 1

Kudos [?]: 62 [0], given: 0

### Show Tags

12 Sep 2006, 05:14
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

.....
Attachments

triangle.JPG [ 9.89 KiB | Viewed 685 times ]

Manager
Joined: 24 Oct 2005
Posts: 169
Followers: 36

Kudos [?]: 189 [0], given: 0

### Show Tags

12 Sep 2006, 08:34
I don't know but it looks E to me. What's the logic to get to b?
Intern
Joined: 04 May 2006
Posts: 40
Followers: 0

Kudos [?]: 0 [0], given: 0

### Show Tags

12 Sep 2006, 14:03
to find the x coordinate we know that D is the midpoint between -8 and 20. so the distance between the 2 is 28. therefore the coordinate corresponding to this midpoint is either 20 -14 or -8+ 14 which both equals 6.
SVP
Joined: 01 May 2006
Posts: 1796
Followers: 9

Kudos [?]: 154 [0], given: 0

### Show Tags

12 Sep 2006, 14:30

As D is at ((20-8)/2,0), thus the answer is between (A) and (B).

I go on (B) because BD,on the graph, seems to be equal to AC

Last edited by Fig on 13 Sep 2006, 06:13, edited 1 time in total.
VP
Joined: 02 Jun 2006
Posts: 1261
Followers: 2

Kudos [?]: 87 [0], given: 0

### Show Tags

12 Sep 2006, 15:28
B. (6, 28)

Let B(x,y)

Given AB = BC

(x+8)^2 +y^2 = (x-20)^2 + y^2

Solving for x, x =6 (x^2 and y^2 cancel out)

Given AC = BC

or 28^2 = (20-6)^2 + y^2
or28^2 - 14^2 = y^2

or y^2 = (28+14)(28-14)

y^2 = 42x14 = 7x6x7x2 = 7^2 x 2^2 x 3

or y = 7x2x1.732

We know y is atleast 14. Eliminate A.

Therefore B(6,28).
CEO
Joined: 20 Nov 2005
Posts: 2898
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Followers: 25

Kudos [?]: 289 [0], given: 0

### Show Tags

12 Sep 2006, 19:43
ps_dahiya wrote:
positive soul wrote:
I don't know but it looks E to me. What's the logic to get to b?

Yes this must be E.
AC = BD = 28

what a silly mistake
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

12 Sep 2006, 19:43
Display posts from previous: Sort by