MathRevolution wrote:
Que: A trader buys a batch of 120,000 computer chips for $3,600,000. He sells \(\frac{2}{5}\) of the computer chips, each at 25 percent above the cost per computer chip. Later, he sells the remaining computer chips at a price per computer chip equal to 25 percent less than the cost per computer chip. What was the percent profit or loss on the batch of computer chips?
(A) Loss of 1%
(B) Loss of 5%
(C) Loss of 7.50%
(D) Profit of 10%
(E) Profit of 22.22%
Solution: Total cost of the 120,000 computer chips = $3,600,000
=> Cost of \(\frac{2}{5}\) of the above computer chips = $ 3,600,000 * \(\frac{2}{5}\) = $1, 440, 000.
These were sold at a 25% higher than the cost price. Thus, the selling price of the above computer chips
=> \(\frac{125}{100}\) *$1,440,100 = $1, 800, 000
Cost of the remaining computer chips = $(3, 600, 000 − 1, 440, 000) = $2, 160, 000
Later, these remaining computer chips were sold at a 25% lower than the cost price. Thus, the selling price of the above computer chips
=> \(\frac{75}{100}\) * $2, 160, 000= $1, 620, 000
Thus, total selling price = $(1, 800, 000 + 1, 620, 000) = $3, 420, 000.
Since total selling price (= $3,420,000) < total cost price (= $3,600,000), there is a loss
Thus, percent loss = \(\frac{[(Cost price − Selling price)]}{ Cost price}\) × 100 (%)
=> \(\frac{(3, 600, 000 − 3, 420, 000) }{ 3, 600, 000}\) × 100 (%) = -5% (Loss)
Therefore, B is the correct answer.
Answer B _________________