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# Ps: expon.

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Manager
Joined: 18 Aug 2005
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26 Sep 2005, 01:23
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If (2x)^y = (x2)^z, the value of y when x is 16 and z is 32 is how much greater than the value of y when x and z are both 8 ?

6

10

16

17

24

Sorry guys for the misuse of exponents=)
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"To win the battle you need to last 15 minutes longer than your enemies"

Last edited by Macedon on 26 Sep 2005, 13:56, edited 1 time in total.
Senior Manager
Joined: 29 Nov 2004
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Location: Chicago
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26 Sep 2005, 06:40
Macedon wrote:
If (2x)y = (x2)z, the value of y when x is 16 and z is 32 is how much greater than the value of y when x and z are both 8 ?

6

10

16

17

24

I hate expon.!!

Please use the ^ sign (it is got by pressing SHIFT and 6), there is no exponents in the question...
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Intern
Joined: 05 Sep 2005
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26 Sep 2005, 07:55
So the question would be:

(2^x)^y = (x^2)^z (hope it right)

If is the case, the answer is:

(2^x)^y = (x^2)^z

<=> 2^(x*y) = x^(2*z)

y=16 and y=6, respectively

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26 Sep 2005, 07:55
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