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# PS: Geometry

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Senior Manager
Joined: 02 Feb 2004
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23 Aug 2005, 07:44
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pls explain
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Senior Manager
Joined: 29 Nov 2004
Posts: 483
Location: Chicago

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23 Aug 2005, 09:27
By SIN relation BO = 1/(sqrt 2)

By TAN relation A0 = 0C = 1/(sqrt 2) so AC = 2/(sqrt 2)

area of triangle = 1/2*AC*BO = 1/2
So area of ABO = 1/4
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Fear Mediocrity, Respect Ignorance

Last edited by ranga41 on 23 Aug 2005, 11:41, edited 1 time in total.
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Joined: 28 Jun 2005
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23 Aug 2005, 09:58
the triangle is a right isosceles triangle with base and height = 1

Area of ABO = half of area of ABC = 1/2*1/2*1*1=1/4
23 Aug 2005, 09:58
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