It is currently 25 Sep 2017, 12:00

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# PS minimum

Author Message
Director
Joined: 02 Mar 2006
Posts: 575

Kudos [?]: 124 [0], given: 0

Location: France

### Show Tags

11 Mar 2006, 15:22
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi,

I don't really understand this pb:

If a+b+c+d is a positive number, a minimum of x of the numbers a,b,c, and d must be positive where x equal to
0
1
2
3
4

Kudos [?]: 124 [0], given: 0

Manager
Joined: 20 Mar 2005
Posts: 201

Kudos [?]: 16 [0], given: 0

Location: Colombia, South America

### Show Tags

11 Mar 2006, 16:23
karlfurt wrote:
Hi,

I don't really understand this pb:

If a+b+c+d is a positive number, a minimum of x of the numbers a,b,c, and d must be positive where x equal to
0
1
2
3
4

I would say 1

as we are adding, we can have 3 negative numbers but if the sum of those three is less than the amount of the only one that is positive, then the sum of a+b+c+d would be positive

Kudos [?]: 16 [0], given: 0

Director
Joined: 02 Mar 2006
Posts: 575

Kudos [?]: 124 [0], given: 0

Location: France

### Show Tags

11 Mar 2006, 16:36
You're right!

I just understood.

I tought x = min(a,b,c,d)...

Kudos [?]: 124 [0], given: 0

Senior Manager
Joined: 22 Nov 2005
Posts: 474

Kudos [?]: 23 [0], given: 0

### Show Tags

11 Mar 2006, 19:55
I also think it is 1. as explained above there could be 3 -ve and 1 +ve, Since 1 is the minimum value > 0. So answer is 1

Kudos [?]: 23 [0], given: 0

11 Mar 2006, 19:55
Display posts from previous: Sort by