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# PS numbers

Author Message
Intern
Joined: 04 May 2011
Posts: 17

Kudos [?]: 41 [0], given: 1

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09 May 2011, 08:05
00:00

Difficulty:

(N/A)

Question Stats:

50% (00:43) correct 50% (01:12) wrong based on 9 sessions

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What is thte total number of different 5-digit integers that contain all of the digits 2,5,4,3,7 and which both the units digit and the thousands digit are odd integers?

a.10 b.8 c.36 d.24 e.12

Kudos [?]: 41 [0], given: 1

VP
Status: There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Joined: 08 May 2009
Posts: 1283

Kudos [?]: 286 [0], given: 10

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09 May 2011, 08:43
As all the digits have to be present in the number hence repetition is not allowed such as 22222 or 33333 and so on.

Thousands and Units place can be taken by 3,5,7 meaning 3*2 ways = 6

Remaining positions can be taken by 2,4 and the remaining Odd digit - 3! ways = 6

thus total ways = 6*6 = 36.
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Kudos [?]: 286 [0], given: 10

Director
Joined: 01 Feb 2011
Posts: 725

Kudos [?]: 147 [0], given: 42

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09 May 2011, 13:51
First arrange odd numbers in units and thousand digit.

This can be done in 3*2 ways(as we have 3 odd numbers)

Rest of 3 digits can be arranged in 3! ways.

Total possible arrangements = 3*2*3! =36

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Kudos [?]: 147 [0], given: 42

TOEFL Forum Moderator
Joined: 16 Nov 2010
Posts: 1602

Kudos [?]: 601 [0], given: 40

Location: United States (IN)
Concentration: Strategy, Technology

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10 May 2011, 06:17
3P2 * 3P3

= 3!/1! * 3!/0!

= 36

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Kudos [?]: 601 [0], given: 40

Re: PS numbers   [#permalink] 10 May 2011, 06:17
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