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# PS: Photo

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Director
Joined: 01 Feb 2003
Posts: 842

Kudos [?]: 122 [0], given: 0

Location: Hyderabad
PS: Photo [#permalink]

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10 Jun 2005, 19:31
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Kudos [?]: 122 [0], given: 0

Senior Manager
Joined: 17 May 2005
Posts: 270

Kudos [?]: 17 [0], given: 0

Location: Auckland, New Zealand

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10 Jun 2005, 20:51
My answer is 6:

If the people are assigned the numbers 1-6 (where 1 is the lowest height and 6 is the greatest)

The positions of 1 and 6 can't be moved...
a b 6
1 c d

2,3,4 and 5 have to be fit into positions a,b,c and d

If a=2, there are 3 possibilities of b: 3,4,5...for each of these possibilities the remaining two numbers can only be placed in 1 order in c & d (as they have to be ascending)

If a=3, there are two possibilities of b:4,5...for each, the remaining two numbers can only be placed in 1 order is c&d

If a=4, there is only one possibility of b:5...and c&d can only be placed in 1 way

a can't be 5 (as there is no person to fit into position b)

Thus total number of ways to arrange = 3+2+1=6

Kudos [?]: 17 [0], given: 0

SVP
Joined: 05 Apr 2005
Posts: 1708

Kudos [?]: 94 [0], given: 0

Re: PS: Photo [#permalink]

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10 Jun 2005, 22:15
i got 5. suppose the heights of the people are 1, 2, 3, 4, 5, and 6.

123
456

124
356

125
346

134
256

135
246

did i miss anything???????????????????????????????????????????????

Kudos [?]: 94 [0], given: 0

Director
Joined: 18 Apr 2005
Posts: 543

Kudos [?]: 37 [0], given: 0

Location: Canuckland

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11 Jun 2005, 00:41
5

I am a bit sleepy but here is my reasoning

I I Tallest
shortest I I

Shortest and tallest fellows have to stand on the opposite sides of different rows.

now we have 4 left we can pick any 2 for 2 positions in the first row 4C2 = 6

however 4th 5th tallest guys cannot be in the first row together so 6-1 = 5

ordering should not matter because there is only 1 way to put ppl in increasing order according to their heights.

Kudos [?]: 37 [0], given: 0

Manager
Joined: 07 Mar 2005
Posts: 93

Kudos [?]: 14 [0], given: 0

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11 Jun 2005, 13:19
fun question.

key was to establish that 1 and 6 must remain in fixed positions. Then the problem becomes managable.

took me a while to realize that though.

I got 5 as well.

Kudos [?]: 14 [0], given: 0

Manager
Joined: 07 Mar 2005
Posts: 93

Kudos [?]: 14 [0], given: 0

Re: PS: Photo [#permalink]

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11 Jun 2005, 13:42
cloudz9 wrote:
HIMALAYA wrote:
i got 5. suppose the heights of the people are 1, 2, 3, 4, 5, and 6.

123
456

124
356

125
346

134
256

135
246

did i miss anything???????????????????????????????????????????????

what about
145
236

and third position for that matter. First row cannot be smaller then second row.

Kudos [?]: 14 [0], given: 0

SVP
Joined: 05 Apr 2005
Posts: 1708

Kudos [?]: 94 [0], given: 0

Re: PS: Photo [#permalink]

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12 Jun 2005, 22:02
cloudz9 wrote:
HIMALAYA wrote:
i got 5. suppose the heights of the people are 1, 2, 3, 4, 5, and 6.

123
456

124
356

125
346

134
256

135
246

did i miss anything???????????????????????????????????????????????

what about
145
236

Oh, i was out of internet for some days, because i was in vacation..., so i couldnot reply on time. anyway it is already explained..............

Kudos [?]: 94 [0], given: 0

Re: PS: Photo   [#permalink] 12 Jun 2005, 22:02
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# PS: Photo

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