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# ps - polygon

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VP
Joined: 30 Sep 2004
Posts: 1480
Location: Germany

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13 Dec 2005, 13:26
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The vertices of an irregular pentagon are A, B, C, D, and E. If AB=5, BC=4, CD=3, DE=10, the length of AE could be which of the followings?

I. 5
II. 7
III. 23

A. I only
B. II only
C. III only
D. I and II only
E. I and II and III only
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Senior Manager
Joined: 05 Oct 2005
Posts: 485

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13 Dec 2005, 13:36
E. Can be I, II or III.

0<AE<23

Is this correct?
Senior Manager
Joined: 03 Nov 2005
Posts: 384
Location: Chicago, IL

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13 Dec 2005, 14:33
I think it's E. There' no restriction for the side AE.
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VP
Joined: 22 Aug 2005
Posts: 1112
Location: CA

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13 Dec 2005, 14:38
rlevochkin wrote:
I think it's E. There' no restriction for the side AE.

If its closed polygon, one side cannot be bigger than "sum of all other four sides(22)".

Like in triangle, one side cannot be bigger than "sum of other two sides".
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Senior Manager
Joined: 03 Nov 2005
Posts: 384
Location: Chicago, IL

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13 Dec 2005, 15:31
Thanks, guys. I had no idea the same rule applies to polygons, too. Kaplan totally omits this point.
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Senior Manager
Joined: 05 Oct 2005
Posts: 485

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13 Dec 2005, 16:24
13 Dec 2005, 16:24
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