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# PS Population (m01q09)

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Manager
Joined: 21 Nov 2010
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28 Nov 2011, 22:35
x2suresh wrote:
good discussion guys.

You view the question in differt way to..

You can rephrase the original problem "% increase is constant over the periods"

% increase inpopulation from 1990-1993 = % increase in population from 1993-96

(4800-3600)/3600 = 33.3%

1996 population = 4800 *1.333 = 6400

Your response makes sense. I'm not sure how close this is to a GMAT question.

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Manager
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02 Dec 2011, 00:19
This is really good question, and very good discussion regarding wording of the Q
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Intern
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30 Nov 2012, 12:17
Like you, I have a problem with this question, but because of wording. It is fine for the question to ask constant growth rate, but it cannot be ambiguous about base years, which is what it did. For instance, what was the population in 1991 or 1992? it isn't 11% (33%/3) year over year, because that ignores the compounding error that will result. By neglecting to specify that the base interval was 3 years, it falsely implies that the rate of pop. growth is YoY, when an answer like 6400 shows clearly that it is not. To compute YoY and go from 3600 to 4800 over 3 years: 3600(1+growthrate)^3=4800. Then dividing both sides by 3600 yields (1+growthrate)^3=(4/3). We don't have the calculating tools on the GMAT to compute logs and thus it is an unfair question.

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Intern
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12 Mar 2013, 05:27
3
KUDOS
(A) 6,000
(B) 6,400
(C) 7,200
(D) 8,000
(E) 9,600

percentage growth of population from 90 to 93 = 33.33 %.
percentage growth of population from 93 to 96 = 33.33 %

Simply add 33% of the population in 93 to 4800
ans = 4800+ 33.33% of 4800 =6400

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Intern
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03 Dec 2013, 12:35
My approach:

Rate from 1,990 to 1,993: (4800-3600)/3600= 1/3
Population in 1,996= 4800* (1+1/3) = 4800*4/3=6,400

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Manager
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06 Dec 2013, 20:45
4800/3600 = 4/3
So, population in 1996 would be 4800 * 4/3 = 6400.
So, B.
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02 Apr 2014, 12:45
$$4800=3600(1 + \frac{R}{100})^3$$

$$(1 + \frac{R}{100})^3=48/36$$

$$Population-in-1996=4800(1+ \frac{R}{100})^3$$

$$Population-in-1996=4800*\frac{48}{36}$$

$$Population-in-1996=6400$$
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Re: PS Population (m01q09)   [#permalink] 02 Apr 2014, 12:45

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# PS Population (m01q09)

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