walker wrote:

I think we should take into account two possible cases: (Ben,x,x,x)(Kelly,x,x,x) and (Kelly,x,x,x)(Ben,x,x,x)

Therefore, we need chose Ben or Kelly for first committee (2C1) and three others not Ben and not Kelly (3C6)

Why are you considering (Kelly, x, x, x)? Kelley should be excluded.

(Ben,x,x,x) is fine.

so the prob = 6c3 / 8c4

**Quote:**

There are 8 members; among them are Kelly and Ben. A committee of 4 is to be chosen out of the 8. What is the probability that Ben is chosen to be in the committee and Kelly is not?

How many possible ways are there to solve this question ?

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