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Manager
Joined: 05 Oct 2005
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22 Nov 2005, 16:40
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hi all
Mike, a DJ at a high-school radio station, needs to play two or three more songs before the end of the school dance. If each composition must be selected from a list of the 10 most popular songs of the year, how many song sequences are available for the remainder of the dance?

(A) 6
(B) 90
(C) 120
(D) 720
(E) 810

Thanks
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Manager
Joined: 19 Sep 2005
Posts: 110

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22 Nov 2005, 20:23
I'm gonna say E. 810

Admittedly I first tried it as a combination problem but my answer wasn't there. However, a sequence of songs tells me order matters.

so he can have a sequence of either 2 songs or 3 songs

2 songs: 10!/8! = 90

3 songs: 10!/7! = 720

then I added them together since it's either 2 OR 3 songs to get 810

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Current Student
Joined: 29 Jan 2005
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22 Nov 2005, 20:44
Exact same strategy as Jennifer because olrder matters. 10P2+10P3= 810

(E)

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22 Nov 2005, 20:44
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