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# PS sequence GMAT prep

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Manager
Joined: 19 Oct 2008
Posts: 94

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20 Mar 2009, 10:56
00:00

Difficulty:

(N/A)

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2+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8=

1. 2^9
2.2^10
3.2^13
4.2^17
5.2^20

Can you please tell me the quickest way to solve this?

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Current Student
Joined: 28 Dec 2004
Posts: 3354

Kudos [?]: 316 [0], given: 2

Location: New York City
Schools: Wharton'11 HBS'12
Re: PS sequence GMAT prep [#permalink]

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20 Mar 2009, 11:34
i get 2^9

u need to realized that 2^2+2^2=2^3

2^3+2^3=2^4

and so on..

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Manager
Joined: 19 Oct 2008
Posts: 94

Kudos [?]: 50 [0], given: 0

Re: PS sequence GMAT prep [#permalink]

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20 Mar 2009, 12:49
Thanks, OA is indeed A.

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Senior Manager
Joined: 16 Jan 2009
Posts: 356

Kudos [?]: 228 [0], given: 16

Concentration: Technology, Marketing
GMAT 1: 700 Q50 V34
GPA: 3
WE: Sales (Telecommunications)
Re: PS sequence GMAT prep [#permalink]

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20 Mar 2009, 13:07
Can we genralise this for 2 atleast?
2^x+2^x= 2^(x+1)

but its not tru for any other number.
_________________

Lahoosaher

Kudos [?]: 228 [0], given: 16

Re: PS sequence GMAT prep   [#permalink] 20 Mar 2009, 13:07
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