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# PS: simple equation

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SVP
Joined: 03 Feb 2003
Posts: 1603

Kudos [?]: 308 [0], given: 0

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02 Jul 2004, 01:01
00:00

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||Z|–2|=1

Kudos [?]: 308 [0], given: 0

SVP
Joined: 03 Feb 2003
Posts: 1603

Kudos [?]: 308 [0], given: 0

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02 Jul 2004, 02:26
do you have a solution or guess them?
remember that modul equtions sometimes have more roots than they seem to have, other times less.

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Intern
Joined: 26 Jan 2003
Posts: 28

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Location: Reality

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02 Jul 2004, 04:52
stolyar wrote:
do you have a solution or guess them?
remember that modul equtions sometimes have more roots than they seem to have, other times less.

Do you mean by this that there are more or less than 4 roots or you are just trying to encourage us to solve instead of guessing.
_________________

Kudos [?]: [0], given: 0

SVP
Joined: 03 Feb 2003
Posts: 1603

Kudos [?]: 308 [0], given: 0

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02 Jul 2004, 04:55
stolyar wrote:
do you have a solution or guess them?
remember that modul equtions sometimes have more roots than they seem to have, other times less.

Do you mean by this that there are more or less than 4 roots or you are just trying to encourage us to solve instead of guessing.

Your answers are correct; however, guessing can be dangerous while dealing with absolute values.

Kudos [?]: 308 [0], given: 0

Intern
Joined: 26 Jan 2003
Posts: 28

Kudos [?]: [0], given: 0

Location: Reality

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02 Jul 2004, 05:03
stolyar wrote:
stolyar wrote:
do you have a solution or guess them?
remember that modul equtions sometimes have more roots than they seem to have, other times less.

Do you mean by this that there are more or less than 4 roots or you are just trying to encourage us to solve instead of guessing.

Your answers are correct; however, guessing can be dangerous while dealing with absolute values.

I actually solved it, though i solve in mind and than get an answer.
_________________

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SVP
Joined: 01 May 2006
Posts: 1794

Kudos [?]: 169 [0], given: 0

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29 Dec 2006, 02:04
||Z|â€“2|= 1

We obtain 2 equations:
> |Z|â€“2 = 1
or
> -(|Z|â€“2)= 1

Thus,
> |Z| = 3
or
> |Z| = 1

Finally, we obtain the 4 solutions for z : {-3, -1, 1, 3}

Kudos [?]: 169 [0], given: 0

29 Dec 2006, 02:04
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