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# ps - sum + sum ?

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VP
Joined: 30 Sep 2004
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ps - sum + sum ? [#permalink]

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20 Oct 2005, 12:31
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:30) correct 0% (00:00) wrong based on 0 sessions

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_________________

If your mind can conceive it and your heart can believe it, have faith that you can achieve it.

Kudos [?]: 425 [0], given: 0

Manager
Joined: 04 Oct 2005
Posts: 246

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20 Oct 2005, 13:00
BbBbBBBBBbBBbBbBBb.....

let q be sum of integers from 75 to 150
so p must simply be q + 151

1/q + 1/(q+151) ... rearrange and you get

2q + 151 / q^2 + q151

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Current Student
Joined: 28 Dec 2004
Posts: 3345

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Location: New York City
Schools: Wharton'11 HBS'12

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20 Oct 2005, 13:00
LCM is q^2-151q

then q-151 goes into LCM q-151 times, and q goes q+151

so you have (q-151+q+151)/(q^2-151q)=2q/(q^2-151q)

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Manager
Joined: 04 Oct 2005
Posts: 246

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20 Oct 2005, 13:08
hehe I did this one again and now get a different result... letting q be the sum of integers..... I let p be q-151...

but then I get A....:S

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Senior Manager
Joined: 05 Aug 2005
Posts: 409

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20 Oct 2005, 19:54
Good one....

Q= p+151 so p=q-151

now solve 1/q-151 + 1/q ..... you will get A

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SVP
Joined: 05 Apr 2005
Posts: 1706

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20 Oct 2005, 20:21
A.

p= sum (75+76+77+............+150)
q= sum (75+76+77+............150+151)
q= sum (75+76+77+............150) +151
q= p+151
p= q-151

given that: 1/p+1/q = ?
= (p+q)/(pq)
replace p with q-151
= (q-151+q)/(q)(q-151)
= (2q-151)/(q^2- 151q)

christoph always has good questions.
a truck of thanxxxxxx

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VP
Joined: 13 Jun 2004
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Location: London, UK
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20 Oct 2005, 21:18
A too

just consider p=q-151 and plug

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SVP
Joined: 03 Jan 2005
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20 Oct 2005, 22:11
nero44 wrote:
hehe I did this one again and now get a different result... letting q be the sum of integers..... I let p be q-151...

but then I get A....:S

You just have to make sure you are clear which is the bigger one ...
_________________

Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.

Kudos [?]: 385 [0], given: 0

20 Oct 2005, 22:11
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