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# PS - x in terms of y

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Senior Manager
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PS - x in terms of y [#permalink]

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03 Oct 2006, 21:22
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Could someone please advise how to do this algebraically (i.e not picking numbers).

Please express x in terms of y for the following and x>-2:

(x^2-16)/(x^2+6x+8)

Thanks

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Senior Manager
Joined: 13 Sep 2006
Posts: 279

Kudos [?]: 23 [0], given: 0

Location: New York

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04 Oct 2006, 06:07
Sorry guys you are right ...please set the equation to equal y

(x^2-16)/(x^2+6x+8) = y

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Current Student
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04 Oct 2006, 07:37
Matrix02 wrote:
Sorry guys you are right ...please set the equation to equal y

(x^2-16)/(x^2+6x+8) = y

FOIL the numerator and denominator.

(x+4)(x-4) / (x+4)(x+2)= y

Cancel out (x+4)

(x-4) / (x+2) = y ---> x-4= yx+2y ---> x-yx=2y+4 ---> x(1-y)=2y+4

x=(2y+4)/(1-y)

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04 Oct 2006, 07:37
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