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# Q: A certain jar contained only pennies and nickles. After 3

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Intern
Joined: 05 Nov 2005
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Q: A certain jar contained only pennies and nickles. After 3 [#permalink]

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20 Nov 2005, 12:58
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Q: A certain jar contained only pennies and nickles. After 3 pennies were removed. how many nickels remained in the jar?
1. The original ration of pennies to nickles in the jar was 7:4
2. After the 3 pennies were removed, the ratio of pennies to nickles in the jar was 3:2

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VP
Joined: 22 Aug 2005
Posts: 1111

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Location: CA

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20 Nov 2005, 13:17
C. 9
P : number of pennies initially
N : number of nickels initially

(1) P/N = 7/4
from ratio we cannot find exact value. insufficient

(2) (P-3/N) = 3/2

or 2P - 3N = 6
insufficient. 2 variables 1 eqn

together: 2 variables, 2 eqns
N = 12
N-3 = 9
_________________

Whether you think you can or think you can't. You're right! - Henry Ford (1863 - 1947)

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Senior Manager
Joined: 15 Apr 2005
Posts: 414

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Location: India, Chennai

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22 Nov 2005, 01:39
C it is. My working is same as Duttist.

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Senior Manager
Joined: 11 May 2004
Posts: 453

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Location: New York

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22 Nov 2005, 13:09
Yea another C. If you know the before and after, you can calculate it...

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Current Student
Joined: 29 Jan 2005
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22 Nov 2005, 22:24
Another C. same method as duttsit

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GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5032

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Location: Singapore

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22 Nov 2005, 22:39
number of pennies and nickles = x

Using (1), all we have is:
original number of pennies = 7x/11
original number of nickles = 4x/11
new number of pennies = 7x/11 - 3

(1) is not sufficient.

Using (2), can't solve either as all we have is the new ratio.

Using both, we can solve for x as we have the new ratio in terms of x and we know it's equal to 3:2.

Ans: C

Kudos [?]: 438 [0], given: 0

22 Nov 2005, 22:39
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