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Q is a certain positive integer. If Q is divided by 5, then

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Q is a certain positive integer. If Q is divided by 5, then [#permalink]

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New post 05 Mar 2003, 05:03
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Q is a certain positive integer.

If Q is divided by 5, then the remainder is 3
If Q is divided by 7, then the remainder is 5

What is Q?

:stupid2
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New post 05 Mar 2003, 05:48
Is this a DS problem????
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New post 05 Mar 2003, 05:54
simple problem solving
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New post 05 Mar 2003, 09:56
Q = 68 :lol:
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New post 05 Mar 2003, 10:20
the answer is 33 not 68 boss!

sac22 is not quite at it better luck next time
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New post 05 Mar 2003, 11:08
ashish_madan wrote:
the answer is 33 not 68 boss!

sac22 is not quite at it better luck next time



Well, both 68 and 33 work.

There is no mentioning that Q is the smallest possible number.....
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New post 05 Mar 2003, 23:20
forgive me guys, I meant 33 - the smallest Q
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New post 10 Jun 2003, 03:46
My approach:

Q=5X+3
Q=7Y+5

Let us add 2:

Q+2=5X+5=5(X+1)
Q+2=7Y+7=7(Y+1)

Thus, Q+2 is evenly divisible both by 5 and by 7. Thus, since we need the smallest Q, we need to do Q=LCM (5, 7)–2=35–2=33.
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Re: Q [#permalink]

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New post 25 Mar 2004, 01:11
stolyar wrote:
Q is a certain positive integer.

If Q is divided by 5, then the remainder is 3
If Q is divided by 7, then the remainder is 5

What is Q?

:stupid2


from the first, Q = 5k+3
from the second, 5k+3 = 5 (7)

5(k-1) = 4 (7)

k-1 = 5 (mod 7)
k = 6 (7)

Q = 5(7m+6) +3 = 35m+33 = 35n -2 where n is an integer
Re: Q   [#permalink] 25 Mar 2004, 01:11
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Q is a certain positive integer. If Q is divided by 5, then

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